Answer:
vertical line
Step-by-step explanation:
If it is possible to draw any vertical line (a line of constant x) which crosses the graph of the relation more than once, then the relation is not a function.
Answer:
Hello,
First equation is false
Second equation is true
Step-by-step explanation:
1)
(4,-3) is a point of the line y=4x-19 since
-3=?4*4-19
-3=-3
2)
(4,-3) is not a point of the line y=1/4x-2 since
-3=? 1/4*4-2
-3=? 1-2
-3≠-1
I have written that because it is difficult for me to understand
"the negative reciprocal of the slope of the first"
the negative reciprocal of 4 should be -1/4.
Equation y=1/4x-2 is false.
The rule for clockwise rotation of 90 degrees about the origin is (-y, x).
So (-1,9) would now be (-9,1).
Hope this Helps!!
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
