Answer:
19 800 lbm of carbon dioxide more.
Explanation:
<u>Taurus</u>
Amount of gasoline used in 5 years = 650 ga/year * 5 years = 3250 ga
amount of carbon dioxide released = 19.8 lbm/ga * 3250 ga = 64 350 lbm
<u>Explorer</u>
Amount of gasoline used in 5 years = 850 ga/year * 5 years = 4250 ga
amount of carbon dioxide released = 19.8 lbm/ga * 4250 ga = 84 150 lbm
Extra amount of CO2 released = 84 150 lbm - 64 350 lbm = 19 800 lbm
A) F = gravitational force
b) G = universal gravitational constant (6.67 × 10-11 N-m2/kg2)
c) m1 = mass of the body 1
d) m2 = mass of body 2
e) r = radius or distance between the two bodies.
Hope this helps!
Answer:
2440 N
Explanation:
As,F=m*a.....
From the question we have
force = 976 × 2.5
We have the final answer as
2440 N
Answer:
See explanations below
Explanation:
According to Newtons second law of motion
F = mass * acceleration
F = ma
If mass of an object is decreased to half, then m₂ = 1/2 m
If acting force is reduced by quarter, then F₂ = 3/4 F
F₂ = m₂a₂
3/4F = 1/2m a₂
Divide both expressions
(3/4F)/F = (1/2m)a₂/ma
3/4 = 1/2a₂/a
3/4 = a₂/2a
4a₂ = 6a
2a₂ = 3a
a₂ = 3/2 a
Hence the acceleration of its motion will be one and a half of its original acceleration.
Answer:
Revolutions made before attaining angular velocity of 30 rad/s:
θ = 3.92 revolutions
Explanation:
Given that:
L(final) = 10.7 kgm²/s
L(initial) = 0
time = 8s
<h3>
Find Torque:</h3>
Torque is the rate of change of angular momentum:

<h3>Find Angular Acceleration:</h3>
We know that
T = Iα
α = T/I
where I = moment of inertia = 2.2kgm²
α = 1.34/2.2
α = 0.61 rad/s²
<h3>
Find Time 't'</h3>
We know that angular equation of motion is:
ω²(final) = ω²(initial) +2αθ
(30 rad/s)² = 0 + 2(0.61 rad/s²)θ
θ = (30 rad/s)²/ 2(0.61 rad/s²)
θ = 24.6 radians
Convert it into revolutions:
θ = 24.6/ 2π
θ = 3.92 revolutions