Answer:
The value is 
Explanation:
From the question we are told that
The first amplitude of the wave is 
The first depth is 
The second amplitude is
The second depth is 
Generally from the spatial wave equation we have

=> 
So considering the ratio of the equation for the two depth

=> 
=> 
=> 
I am sorry if it didn't helped
answers;
Calculate the buoyant force of a piece of cork of 8cm3 that floats in water. Density of cork is 207kg/m3. ?
I need the mass, in order to get the volume to apply t to the Buoyancy formula of: B=(W)object=(m)object(g)
Explanation:
From Archimedes Principle, any object partially or totally submerged in a fluid is buoyed upwards with a force equal to the weight of the displaced fluid.
∴
B
=
ρ
f
l
V
f
l
g
=
1000
k
g
/
m
3
×
8
×
10
−
6
m
3
×
9
,
8
m
/
s
2
=
0
,
0784
N
(assuming the density of water is at standard temperature and pressure, and that the cork is totally submerged as it floats in the water
it's not the answer of your question ⁉️ but it is similar ........
Answer:
Should be B
Explanation:
As the light enters the prism at an angle, the glass causes the light to travel slower. The speed is affected by the frequency of the light. So each frequency is slowed by a different amount, causing the colors to separate.
Hope this helps!
Answer:
Explanation:
A ) When gymnast is motionless , he is in equilibrium
T = mg
= 63 x 9.81
= 618.03 N
B )
When gymnast climbs up at a constant rate , he is still in equilibrium ie net force acting on it is zero as acceleration is zero.
T = mg
= 618.03 N
C ) If the gymnast climbs up the rope with an upward acceleration of magnitude 0.600 m/s2
Net force on it = T - mg , acting in upward direction
T - mg = m a
T = mg + m a
= m ( g + a )
= 63 ( 9.81 + .6)
= 655.83 N
D ) If the gymnast slides down the rope with a downward acceleration of magnitude 0.600 m/s2
Net force acting in downward direction
mg - T = ma
T = m ( g - a )
= 63 x ( 9.81 - .6 )
= 580.23 N