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Sonbull [250]
3 years ago
5

Please someone help me.

Physics
1 answer:
katovenus [111]3 years ago
5 0

Answer:

acceleration of the car is 3 m\s^2

Explanation:

from rest means the initial velocity (vi) is zero

time = 5s

final velocity (vf) = 15m\s

a = vf - vi \ t

a = (15-0) \ 5

a= 3 m\s^2

which means that the car is speeding up 3 meters every second

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Please Help!
irga5000 [103]

The maximum force that the tires can exert on the road before slipping is 16200 N.

From the information in the question;

The coefficient of static friction =  0.9

The mass of the car = 1800 kg

Using the formula;

μ = F/R

μ  = coefficient of static friction

F = force on the tires

R = the reaction force

But recall that the reaction is equal in magnitude to the weight of the car.

W=R

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Making F the subject of the formula;

F = μR

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F =  18000 N × 0.9

F = 16200 N

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Learn more: brainly.com/question/18754989

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