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snow_lady [41]
3 years ago
13

A square metal plate of edge length 6.4 cm and negligible thickness has a total charge of 6.6 x 10-6 C. Estimate the magnitude E

of the electric field just off the center of the plate (at, say, a distance of 0.71 mm from the center) by assuming that the charge is spread uniformly over the two faces of the plate. Express your answer in terms of N/C.
Physics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

E=9.1\times 10^7 N/C

Explanation:

We are given that

Length of side,l=6.4 cm=6.4\times 10^{-2} m

1 m=100 cm

Total charge,q=6.6\times 10^{-6} C

We have to find the magnitude E of the electric field just off the center of the plate.

Area charge density,\sigma=\frac{q}{A}=\frac{q}{l^2}=\frac{6.6\times 10^{-6}}{(6.4\times 10^{-2})^2}

\sigma=16.1\times 10^{-4}C/m^2

Electric field,E=\frac{\sigma}{2\epsilon_0}

Where \epsilon_0=8.85\times 10^{-12}

Substitute the values

E=\frac{16.1\times 10^{-4}}{2\times 8.85\times 10^{-12}}

E=9.1\times 10^7 N/C

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