Answer:
Her speed on the summit was 35 mph.
Step-by-step explanation:
Her speed on the summit was "x" mph while her speed while climbing was "x - 10" mph. The distance she rode uphill was 55 miles and on the summit it was 28 miles. The total time she explored the mountain was 3 hours. Therefore:
time uphill = distance uphill / speed uphill = 55 / (x - 10)
time summit = distance summit / speed summit = 28 / x
total time = time uphill + time summit
3 = [55 / (x - 10)] + 28 / x
3 = [55*x + 28*(x - 10)]/[x*(x - 10)]
3*x*(x - 10) = 55*x + 28*x - 280
3x² - 30*x = 83*x - 280
3x² - 113*x + 280 = 0
x1 = {-(-113) + sqrt[(-113)² - 4*(3)*(280)]}/(2*3) = 35 mph
x2 = {-(-113) - sqrt[(-113)² - 4*(3)*(280)]}/(2*3) = 2.67 mph
Since her speed on the uphill couldn't be negative the speed on the summit can only be 35 mph.
Answer: Kate = 40/3 Her father = 50
Step-by-step explanation:
Let Kate's age in the present be K
And Kate's father's age in the present be F
3(K+5) = F+5
6(K-6) = F-6
Rearrange the first equation to get
3K+15 = F+5
3K+10 = F
Substitute that into the second question
6K-36 = 3K+10-6
3K = 40
K = 40/3
So F = 3*40/3+10 = 50
Answer:He is wearing a coat and the temperature is below 30°F.
Step-by-step explanation:
Answer:
- 2(L +W) ≤ 600
- W ≤ 200
- L ≥ 2W
Step-by-step explanation:
We assume the problem wording means the length is to be at least 2 times <em>as long as</em> the width. (<em>Longer than</em> usually refers to a difference, not a scale factor.)
If we let "W" and "L" represent the width and length, respectively, then we can translate the problem statement to ...
2(L + W) ≤ 600 . . . . . . the perimeter is twice the sum of length and width
W ≤ 200 . . . . . . . . . . . . the width is at most 200 inches
L ≥ 2W . . . . . . . . . . . . . the length is at least twice the width
Answer:
Part 1
a. .27 < .50
b. .33 < .75
c. 4.60 > 3.89
d. .76 > .08
e. .09 < .11
f. 3.33 > 3.30
Part 2
.27(2)= .54
.50(1)= .50
.27(2)= .54 is larger than .50 because if it was money, .54 is greater than .50
Step-by-step explanation:
