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Elanso [62]
3 years ago
11

What is the maximum vertical distance between the line y = x 30 and the parabola y = x2 for −5 ≤ x ≤ 6?

Mathematics
1 answer:
Arlecino [84]3 years ago
7 0
Set y1=x+30 and y2=x^2, plugged those into the distance formula assuming x=a<span>, 
</span><span>
d=rad(<span>(y2−y1<span>)^2)
</span></span></span><span>d(x)=x^2−x−30

</span>All you have to do is to maximize the given quadratic function. I hope that this is the answer that you were looking for and it has helped you.
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trapecia [35]

Answer:

54 because I don't know I can't explain

7 0
2 years ago
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Find the value of x?
jekas [21]
Hello!
The left triangle have two same side length so the two bottom angles are the same which is (180-56)/2=62
See the left triangle bottom right angle and the right triangle bigger angle have the sum of 180 degree so the bigger angle=180-62=118
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Have a great day!
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3 years ago
Find the range of the data in the box plot below.
kifflom [539]

Answer:

16

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3 0
2 years ago
Solve the equation.9x^2 + 16 = 0
REY [17]

Step 1

Given;

9x^2+16=0

Required: To solve the equation.

Step 2

Solve the equation

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Answer;

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4 0
1 year ago
You calculated probabilities involving various blood types. Some of your answers depended on the assumption that the outcomes de
Natali5045456 [20]

Answer:

a) The events are disjoint, because a person cannot have blood type A and blood type B at the same time.

b) The events are independent, because the probability of having blood type does not depend on other persod having blood type B.

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Step-by-step explanation:

a) Let the events be:

A: "the person has blood type A

B: the person has blood type B

As a person can only have one blood type these events are disjoint.

b) If we examine two people, let the events be that the first is blood Type A and the second blood Type B:

The events are independent because the probability of the first person having blood type A does not influence the probability of the second person having blood type B (unless the two people are related).

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P(A∩B)=P(A)×P(B)

Given the events A and B which are disjoint:

P(A∩B)=0

Hence, A and B could be independent events if and only if the probability of one of the events is 0.

3 0
3 years ago
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