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3 years ago

Y intercept = ? x intercept = ? I need help in my Aleks homework :)

Mathematics

1 answer:

IgorLugansk [536]3 years ago

5 0

Answer:

y-intercept: 2

x-intercept: -2, 4

Step-by-step explanation:

Y-intercepts and x-intercepts are points on the graph that are on the y-axis and x-axis, respectively.

Looking at the graph, the graph passes through the y-axis at y=2. Therefore, the y-intercept is 2.

Looking at the graph, the graph passes through the x-axis at x=-2 and x=4. Therefore, the x-intercepts are -2 and 4.

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Please answer this correctly

marshall27 [118]

Answer:

hello

Step-by-step explanation:

u sayh-e-l-l-o yW

6 0

3 years ago

Round the number. Write the result as a product of a single digit and a power of 10. 0.00000124

-BARSIC- [3]

0.000001

10^-6

hope this helps :))

8 0

2 years ago

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PLEASE HELP ASAP !!

wariber [46]

Answer:

First figure: $954cm^3$

Second figure: $1,508yd^3$

Third figure:

Height= q
Side length = r

Fourth figure:  $726cm^3$

Explanation:

A. First figure:

1. Formula:

$\text{Volume of a cylinder}=\pi \times radius^2\times length$

2. Data:

radius = 9cm / 2 = 4.5cm

length = 15 cm

3. Substitute in the formula and compute:

$Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3$

B. Second figure

1. Formula:

$\text{Volume of a leaned cylinder}=\pi \times radius^2\times height$

2. Data:

radius = 12yd

height = 40 yd

3. Substitute and compute:

$Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3$

C) Third figure

a) The height is the segment that goes vertically upward from the center of the base to the apex of the pyramid, i.e. q .

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e. r .

When the base of the pyramid is a square the four edges of the base have the same side length.

D) Fourth figure

1. Formula

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

$Volume=(1/3)B\times H$

2. Data:

height: H = 18cm

side length of the base: 11 cm

3. Calculations

a) Calculate the area of the base.

The base is a square of side length equal to 11 cm:

$\text{Area of the base}=B=(11cm)^2=121cm^2$

b) Volume of the pyramid:

$Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3$

4 0

3 years ago

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1.a) Convert 81° into grade. 10

Kazeer [188]

Step-by-step explanation:

I hope it helps man this much .

6 0

3 years ago

Solve x2 + 14x + 17 = –96 for x

jarptica [38.1K]

For this case we have to:

Given the quadratic equation of the form:

$ax ^ 2 + bx + c = 0$

The roots are given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

If we have: $x ^ 2 + 14x + 17 = -96$

We can rewrite it in the following way:

$x ^ 2 + 14x + 17 + 96 = 0\\x ^ 2 + 14x + 113 = 0$

Where:

$a = 1\\b = 14\\c = 113$

Where we have:

$x = \frac {-14 \pm \sqrt {(14) ^ 2-4 (1) (113)}} {2 (1)}$

$x = \frac {-14 \pm \sqrt {(196-452)}} {2}$

$x = \frac {-14 \pm \sqrt {-256}} {2}$

By definition: $\sqrt {-1} = i$

$x = \frac {-14 \pm \sqrt {256} i} {2}$

$x = \frac {-14 \pm16i} {2}$

$x = \frac {-14} {2} \pm \frac {16i} {2}$

$x = -7 \pm8i$

Thus, the roots are given by imaginary numbers:

$x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i$

Answer:

$x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i$

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3 years ago

Read 2 more answers