Answer:
Jaw saw an average of 6 birds each day
Step-by-step explanation:
Given: One day, Jean saw 7 birds. The next day, she saw 11 birds. The next day, she saw no birds.
To find: average number of birds Jean saw each day
Solution:
Average is a central value of a set of terms.
Average of terms 
is given by 
Number of birds, Jean saw on day one 
= 7
Number of birds, Jean saw on the second one 
= 7
Number of birds, Jean saw on the third one 
= 7
So,
average number of birds Jean saw each day = 
Therefore,
Jaw saw an average of 6 birds each day
Answer:
The probability is 0.081
Step-by-step explanation:
Here, we want to calculate the probability that the 3rd inspection will be defective.
What this means is that the first two would
not be defective.
Probability of having a defective DVD = 10% = 10/100 = 0.1
Probability of not having a defective DVD = 1 -0.1 = 0.9
So the probability of third being defective = Probability of first not defective * Probability of second not defective * Probability of third defective
= 0.9 * 0.9 * 0.1 = 0.081
Answer:
-2
Step-by-step explanation:
Bc÷2a
5×-4÷2×5
-20÷10
-2
-4.2c+4.8d is the answer to this equation.
