Answer:
The answer is 30 g of sodium hydrocarbonate
Explanation:
This is a acid-base reaction, so in order to neutralise the spilled acid, the mol of spilled acid should be calculated.
M = n / V => n = M x V = 0.028 x 6.2 = 0.1736 mol
Since 1 mol of sulfuric acid generates 2 mol of H⁺, so the mole of H⁺ is 0.3472 mol or 0.35 mol with two significant figures.
To neutralized the acid, we need at least the same mole of base, so we need at least 0.35 mol of NaHCO₃, which can be converted to its mass at 29.4 g.
Since the answer need to be expressed in two significant figures and also need to make sure to neutralize all the acid, so we will use a little excess base. The answer is 30 g.
Answer:
0.375 moles of CaCO₃ are required
Explanation:
Given data:
Number of moles of sulfamic acid = 0.75 mol
Number of moles of calcium carbonate required = ?
Solution:
Chemical equation:
2H₃NSO₃ + CaCO₃ → Ca(SO₃NH₂)₂ + CO₂ + H₂O
Now we will compare the moles of H₃NSO₃ and CaCO₃ .
H₃NSO₃ : CaCO₃
2 : 1
0.75 : 1/2×0.75 = 0.375 mol
Thus, 0.375 moles of CaCO₃ are required.
Explanation:
The given data is as follows.
Volume of lake = 
= 
Concentration of lake = 5.6 mg/l
Total amount of pollutant present in lake = 
= 
mg
= 
kg
Flow rate of river is 50 
Volume of water in 1 day = 
= 
liter
Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 
or 
Flow rate of sewage = 
Volume of sewage water in 1 day = 
liter
Concentration of sewage = 300 mg/L
Total amount of pollutants = 
or 
Therefore, total concentration of lake after 1 day = 
= 6.8078 mg/l
= 0.2 per day
= 6.8078
Hence, 
= 
= 
= 1.234 mg/l
Hence, the remaining concentration = (6.8078 - 1.234) mg/l
= 5.6 mg/l
Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.
Answer;
The answer is No,
Explanation;
-The intersection of two parallel half-planes A and B is either a half-plane (either A or B, when A and B have similar orientation) or the empty set (when A and B have opposite orientation).
-When A and B are not parallel, their intersection is a maximal open region bounded by the two lines that define A and B, respectively. In this case, the intersection always exists and it is never a half-plane.
Oxygen is the second most abundant gas in our atmosphere.
