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Ludmilka [50]
2 years ago
12

"Reduce, reuse, recycle." Give examples of how one or more of

Chemistry
1 answer:
Anarel [89]2 years ago
6 0

Answer:

Examples of how the ideas can be applied to the issues and practices of hydraulic fracturing for the acquisition of shale gas are;

Reuse; The produced water in obtained from oil and gas well production are reused for fracking, drilling, and if the water is good enough, it can be used for farming

Reduce; The use of recycled brine and water in drilling and fracking process reduces the application of freshwater in the those processes and reduces pollution of natural water sources

Recycle; Recycling involves creating products from waste. In the hydraulic fracturing process approximately 13 percent of the water produced and the flowback water are recycled to be used more than once thereby reducing the net consumption of freshwater

Explanation:

In hydraulic fracturing, also known informally as fracking, is the drilling method used in oil and gas well development process that makes use of water sand and chemical injection through the well bore to open and widen cracks in the bedrock formations in the areas around the wellbore.

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When 100 photons of light pass through a sample and 64 photons are detected after the passage of light, the number of photons transmitted through the sample is 64.

This is based on the methods of calculating the absorbance of light, which is depicted as the higher the amount of light transmission, the lower the amount of light absorbed.

Thus, when 64 photons of light in 100 photons are detected, 64 photons are transmitted, and therefore, the number of photons absorbed is 36.

Hence, hypothetically, if 100 photons of light are transmitted, 0 photons of light will be absorbed.

Therefore, in this case, it is concluded that the correct answer is 64 photos.

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5 0
2 years ago
Hey, i need help. the teacher provided notes but they don’t explain ANYTHING.
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Answer:

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5 0
3 years ago
An unknown compound has a percent composition of 52.10% potassium, 15.8% carbon, and 32.1% oxygen. The molar mass of the compoun
lianna [129]
To determine the empirical formula and the molecular formula of the compound, we assume a basis of the compound of 100 g. We do as follows:

       Mass              Moles                     
K    52.10     52.10/39.10 = 1.33         1.33/1.32 ≈ 1
C    15.8       15.8/12         = 1.32         1.32/1.32 ≈ 1
O     32.1      32.1 / 16       =  2.01        2.01/1.32 ≈ 1.5

The empirical formula would most likely be KCO.
The molecular formula would be K2C2O3.
4 0
3 years ago
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HACTEHA [7]

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