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astra-53 [7]
2 years ago
15

Help !.!.!.!.!.!.!!.!.!.!.!.!.!.!.!.!.!.!.!.!.

Mathematics
2 answers:
algol132 years ago
7 0

Answer:

<em>~ 1.5 km of the actual path ~</em>

Step-by-step explanation:

Let us plan out our steps, and solve for each:

<em>1. Given the information, let us create a proportionality as such:</em>

      1       =           10,000      ⇒   x - centimeters of the actual path

      15                      x

<em>2. Now let us cross multiply, and solve through simple algebra for x:</em>

10,000 * 15 = x,

x =<em> </em>150,000 centimeters of the actual path

<em>3. We can see that we have to determine the km of the actual path, so let us convert the 150,000 centimeters ⇒ kilometers:</em>

150,000 cm <em>⇒  </em><em>1.5 km of the actual path</em>

Elena-2011 [213]2 years ago
6 0

Answer:

1.5 km

Step-by-step explanation:

15 cm * 10 000 = 150 000 cm = 1.5 km

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Find all angles and pls show steps ​
Ghella [55]

Answer:

Both angles have a measure of 134degrees, y = 27degrees.

Step-by-step explanation:

As per what is given in the problem:

There are 2 parallel lines, both are intersected by a transversal.

Remember the theorem, when two parallel lines are intersected by a transversal, then the alternate exterior angles are congruent.

The is meanse that:

3y + 53 = 7y - 55

Solve using inverse operations:

3y + 53 = 7y - 55

     +55         +55

3y + 108 = 7y

-3y            -3y

108 = 4y

/4      /4

27 = y

Now, substitute back in to find the value of the angle:

3y + 53

y = 27

3 ( 27 ) + 53

81 + 53

= 134

Since the angles are alternate exterior, they are congruent, hence both angles have a measure of 134degrees.

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2 years ago
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2 years ago
A group consists of 6 men and 5 women. Five people are selected to attend a conference. In how many ways can 5 people be selecte
cluponka [151]

Answer:

462

6

1.2%

Step-by-step explanation:

Since the questions are combinations, we must apply the combination formula, which is as follows:

n C r = (n!) / (r! (n-r)!)

Because there are 6 men and 5 women, there are a total of 11 people.

Thus:

n = 11

In the first question in how many ways can 5 people be selected from this group of 11, r = 5.

Replacing in the formula:

11 C 5 = (11!) / (5! * (11-5)!)

11 C 5 = (11!) / (5! * 6!)

11 C 5 = 462

In the second question, in how many ways can 5 men be selected from the 6 men, here n = 6 and r = 5, replacing we are left with:

6 C 5 = (6!) / (5! * (6-5)!)

6 C 5 = (6!) / (5! * 1!)

6 C 5 = 6

In the last question of what is the probability that the selected group is all men, we have that it is the combination of the two previous questions. Since the total would be part A it would be the total of the combinations of choosing 5 of 11 people and part B of the 6 men that there are the combinations of choosing 5.

Divide the two values ​​from parts A and B to get ...

(result from part B) / (result from part A) = (# of ways to pick 5 men) / (# of ways to pick 5 people)

(result from part B) / (result from part A) = 6/462

(result from part B) / (result from part A) = 0.012

In other words, the probability is 1.2%

7 0
3 years ago
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