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pashok25 [27]
3 years ago
15

If the equation y = 1/6(x + 12) were graphed in the xy-plane, which of the following statements would be true of the graphed lin

e?
A. It would be perpendicular to the graph of y = 1/6x + 3.

B. It would be parallel to the graph of 12y = 2x + 3.

C. It would have the same slope as the graph of x + 6y = 18.

D. It would have the same y‑intercept as the graph of y = 1/6x + 12.
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0
The answer would be B it would be parallel to the graph of 12y = 2x + 3
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luda_lava [24]

Answer:

B is correct

Step-by-step explanation:

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Answer:

<h3>Q 17</h3>

a is supplementary with 36 and b is supplementary with 113.

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Correct choice is D

<h3>Q 2</h3>
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<h3>Q 3</h3>

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2 years ago
Order the following numbers from greatest to least
Kazeer [188]
The square root of 7: 2.64575
-0.3
(-7/4)= -1.75
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7 0
3 years ago
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Please help me asap<br>​
Lera25 [3.4K]

Answer:

Step-by-step explanation:

From the picture attached,

∠4 = 45°, ∠5 = 135° and ∠10 = ∠11

Part A

∠1 = ∠4 = 45°  [Vertically opposite angles]

∠1 + ∠3 = 180° [Linear pair of angles]

∠3 = 180° - ∠1

     = 180° - 45°

     = 135°

∠2 = ∠3 = 135°  [Vertically opposite angles]

∠8 = ∠5 = 135° [Vertically opposite angles]

∠5 + ∠6 = 180° [Linear pair of angles]

∠6 = 180° - 135°

∠6 = 45°

∠7 = ∠6 = 45° [Vertically opposite angles]

By triangle sum theorem,

m∠4 + m∠7 + m∠10 = 180°

45° + 45° + m∠10 = 180°

m∠10 = 180° - 90°

m∠10 = 90°

m∠10 = m∠12 = 90°  [Vertically opposite angles]

m∠10 = m∠11 = 90° [Given]

Part B

1). ∠1 ≅ ∠4  [Vertically opposite angles]

2). ∠7 + ∠5 = 180° [Linear pair]

3). ∠9 + ∠10 = 180° [Linear pair]

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3 years ago
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yaroslaw [1]

Answer: x=4, y=-2

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3 years ago
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