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3 years ago

a television on sale for 1/4 off original price. Original price is 120 more then sale price. What is original price of tv

Mathematics

1 answer:

agasfer [191]3 years ago

4 0

Answer:

Original Price = 160

Sale Price =40

Step-by-step explanation:

Let Original Price be x and Sale Price be y

y=1/4 of x (Equation 1)

x=120+y (Equation 2)

Put value of x from equation 2 in equation 1

y= (1/4)*(120+y)

y=120/4 + y/4

y-y/4=30

3y/4=30

y=30*4/3

y=40

Put value of y in Equation 2

x=120+40

x=160

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The given function is

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c is the phase shift

d is the vertical shift

By comparing the two functions

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The equation of the midline is

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Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

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10 months ago

Given that a function, g, has a domain of -1 ≤ x ≤ 4 and a range of 0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8, select the st

notka56 [123]

Options

(A)g(5) = 12
(B)g(1) = -2
(C)g(2) = 4
(D)g(3) = 18

Answer:

(D)g(3) = 18

Step-by-step explanation:

Given that the function, g, has a domain of -1 ≤ x ≤ 4 and a range of 0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8

Then the following properties must hold

The value(s) of x must be between -1 and 4
The values of g(x) must be between 0 and 18.
g(-1)=2
g(2)=9

We consider the options and state why they are true or otherwise.

Option A: g(5)=12

The value of x=5. This contradicts property 1 stated above. Therefore, it is not true.

Option B: g(1) = -2

The value of g(x)=-2. This contradicts property 2 stated above. Therefore, it is not true.

Option C: g(2) = 4

The value of g(2)=4. However by property 4 stated above, g(2)=9. Therefore, it is not true.

Option D: g(3) = 18

This statement can be true as its domain is in between -1 and 4 and its range is in between 0 and 18.

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