The graph above shows a polynomial function with ___
1 answer:
Your question: The graph above shows a polynomial function with ___
<h3>Answer: B, a polynomial function with an odd degree and a positive leading coefficient</h3>Step-by-step explanation: If the degree of a polynomial f(x) is even and the leading coefficient is positive, then f(x) → ∞ as x → ±∞. ... If f(x) is an odd degree polynomial with positive leading coefficient, then f(x) →-∞ as x →-∞ and f(x) →∞ as x → ∞.
I hope this helps, mate!
You might be interested in
Answer:
see explanation
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h. k) are the coordinates of the vertex and a is a multiplier
here (h, k) = (- 6, - 1), thus
y = a(x + 6)² - 1
To find a substitute one of the roots into the equation
Using (- 3, 0), then
0 = a(- 3 +6)² - 1
0 = 9a - 1 ( add 1 to both sides )
1 = 9a ( divide both sides by 9 )
a = , thus
y = (x + 6)² - 1 ← in vertex form
Expand factor and simplify
y = (x² + 12x + 36) - 1 ← distribute
y = x² +
x + 4 - 1
= x² +
x + 3 ← in standard form