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Anna [14]
3 years ago
7

For each of the variables described below, indicate whether it is a quantitative or a categorical (qualitative) variable. Also,

indicate the level of measurement for the variable: nominal, ordinal, interval, or ratio. Make sure your responses are the most specific possible.
Variable,Type of variable and Level of measurement

(a) Native language (Quantitative, Categorical) (Nominal, Ordinal,Interval, Ratio)
(b) Temperature (in degrees Fahrenheit) (Quantitative, Categorical) (Nominal, Ordinal,Interval, Ratio)
(c) Closing price (in dollars) of a stock (Quantitative, Categorical) (Nominal, Ordinal,Interval, Ratio)
Mathematics
1 answer:
mart [117]3 years ago
4 0
Answer is a because the question
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The perimeter of a rectangular field is 350m. If the length of the field is 99m, what is it’s width?
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Answer:

The width of the field is 3.535353535m

Step-by-step explanation:

350÷99=3.535353535

Proof: 99×3.535353535=350

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3 years ago
Need help plzzzzz The first one and the second one plZ
solong [7]

From both sides of the equation, 4 should have been subtracted.

The solution should look like this:

X + 4  =  28

From each side, subtract  4 :

<em>X  =  24</em>

I'd like to demonstrate more steps, but the answer has already popped up, so there aren't any more steps.

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There are n applicants for the director of computing. The applicants are interviewed independently by each member of the three-p
Delvig [45]

Answer:

for  n =  3

       Z(3) = 0.26  

for  n =  10

       Z(3) = 0.028

Step-by-step explanation:

from the question we are that

  The  number of applicant is n

  The  number of  people on the committee is N = 3

 

Generally given that the applicant ranking is random the probability of a candidate being accepted is mathematically represented as

       Z(n) =  N  *  \frac{1}{n} *  \frac{1}{n}  *  \frac{n-1}{n}  + \frac{1}{n} *  \frac{1}{n} * \frac{1}{n}

Now  for  n =  3

       Z(3) =  3  *  \frac{1}{3} *  \frac{1}{3}  *  \frac{3-1}{3}  + \frac{1}{3} *  \frac{1}{3} * \frac{1}{3}      

         Z(3) = 0.26            

Now  for  n =  10

       Z(3) =  3  *  \frac{1}{10} *  \frac{1}{10}  *  \frac{10-1}{10}  + \frac{1}{10} *  \frac{1}{10} * \frac{1}{10}      

         Z(3) = 0.028

3 0
3 years ago
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