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2 years ago

Rank from most conductive to least conductive: AlCl3, C6H12O6, KBr, C3H7OOH ??

Chemistry

2 answers:

Lyrx [107]2 years ago

8 0

Answer:

The order is:

AlCl₃ > KBr > C₃H₇COOH > C₆H₁₂O₆

Explanation:

A compound is conducting in nature (in soluble form) if it is ionic.

More the ions produced by a compound more the conductive the compound is.

In the given compounds C₆H₁₂O₆ is non electrolytic or non ionic. It will dissolve in water and will not furnish any ion thus it will be non conducting (least)

C₃H₇COOH: It is a weak electrolyte and will dissociate very less in water and thus it will be conducting but less than a strong elecrolyte.

KBr and AlCl₃ both are ionic and will dissociate completely however AlCl₃ will produce four ions while KBr will give only two ions per molecule.

Hence AlCl₃ is more conducting

The order is:

AlCl₃ > KBr > C₃H₇COOH > C₆H₁₂O₆

dexar [7]2 years ago

3 0

One needs to rank from the most conductive to the least conductive among the formulas that are given in the question. The ranking will be as given below.
1. AlCl3
2. KBr
3. C3H7OOH
4. C6H12O6

I hope that this is the answer that you were looking for and the answer has actually come to your desired help.

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2 years ago

In the decomposition of water, why is twice as much hydrogen as oxygen formed?(1 point)

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5 0

2 years ago

A chemist titrates of a hypochlorous acid solution with solution at . Calculate the pH at equivalence. The of hypochlorous acid

const2013 [10]

The question is incomplete, here is the complete question:

A chemist titrates 110.0 mL of a 0.2412 M hypochlorous acid (HCIO) solution with 0.0613 M NaOH solution at 25°C. Calculate the pH at equivalence. The pKa of hypochlorous acid is 7.50. Round your answer to 2 decimal places

Answer: The pH of the solution is 10.09

Explanation:

To calculate the volume of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HClO$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=0.2412M\\V_1=110.0mL\\n_2=1\\M_2=0.0613M\\V_2=?mL$

Putting values in above equation, we get:

$1\times 0.2412\times 110.0=1\times 0.0613\times V_2\\\\V_2=\frac{1\times 0.2412\times 110.0}{1\times 0.0613}=432.8mL$

At equivalence, the number of moles of acid is equal to the number of moles of base. Also, the moles of salt which is NaClO will also be the same.

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For HClO:

Molarity of HClO solution = 0.2412 M

Volume of solution = 110.0 mL

Putting values in equation 1, we get:

$0.2412M=\frac{\text{Moles of HClO}\times 1000}{110}\\\\\text{Moles of HClO}=\frac{(0.2412\times 110)}{1000}=0.026532mol$

For NaClO:

Moles of NaClO = 0.026532 moles

Volume of solution = [432.8 + 110] mL = 542.8 mL

Putting values in above equation, we get:

$\text{Molarity of NaClO}=\frac{0.026532\times 1000}{542.8}=0.0489M$

To calculate the pH of the solution, we use the equation:

$pH=7+\frac{1}{2}[pK_a+\log C]$

where,

$pK_a$ = negative logarithm of weak acid which is hypochlorous acid = 7.50

C = concentration of the salt = 0.0489 M

Putting values in above equation, we get:

$pH=7+\frac{1}{2}[7.50+\log (0.0489)]\\\\pH=7+3.09=10.09$

Hence, the pH of the solution is 10.09

4 0

2 years ago

A compound with an empirical formula of CH2O has a molar

NeTakaya

Answer:

c2h4o2

Explanation:

I am using my cell. This could take a bit

The Empical formula has a mass of

C 12

2H 2

O 16

total = 30

The molecular mass is given as 60 which is 2 times the empirical mass. Therefore multiply each element by 2 in the empirical formula.

You get C2H4O2

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2 years ago