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mr_godi [17]
3 years ago
7

Rank from most conductive to least conductive: AlCl3, C6H12O6, KBr, C3H7OOH ??

Chemistry
2 answers:
Lyrx [107]3 years ago
8 0

Answer:

The order is:

AlCl₃ > KBr > C₃H₇COOH > C₆H₁₂O₆

Explanation:

A compound is conducting in nature (in soluble form) if it is ionic.

More the ions produced by a compound more the conductive the compound is.

In the given compounds C₆H₁₂O₆ is non electrolytic or non ionic. It will dissolve in water and will not furnish any ion thus it will be non conducting (least)

C₃H₇COOH: It is a weak electrolyte and will dissociate very less in water and thus it will be conducting but less than a strong elecrolyte.

KBr and AlCl₃ both are ionic and will dissociate completely however AlCl₃ will produce four ions while KBr will give only two ions per molecule.

Hence AlCl₃ is more conducting

The order is:

AlCl₃ > KBr > C₃H₇COOH > C₆H₁₂O₆

dexar [7]3 years ago
3 0
One needs to rank from the most conductive to the least conductive among the formulas that are given in the question. The ranking will be as given below.
<span>1. AlCl3
2. KBr
3. C3H7OOH
4. C6H12O6
</span>
I hope that this is the answer that you were looking for and the answer has actually come to your desired help.
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