Why is water a very good substance for use in cooling systems of automobiles?

Chemistry

1 answer:

Inessa [10]3 years ago

7 0

It can absorb thermal energy without a large change in temperature.

You might be interested in

Describe the motion of a pendulum in terms of kinetic and potential energy. As the pendulum moves from its greatest to lowest he

Bezzdna [24]

Highest height : Potential energy = high | Kinetic energy = low

Lower height: kinetic Potential energy = low | Kinetic energy = high

*Remember it by when its higher thats when it has "high potential" :)*

6 0

3 years ago

I need help with 2, 3, and 4 please help i will give the brainliest

Sphinxa [80]

Answer:

2=2.28*10^5

3=3.98*10^3

4=5.76*10^3

8 0

3 years ago

What mass of butane in grams is necessary to produce 1.5×103 kj of heat what mass of co2 is produced?

kari74 [83]

The heat of reaction (i.e. combustion) of butane ( $C_{4} H_{10}$ ) when reacted with oxygen ( $O_{2}$ )  is -2658 kJ/mol butane, and the chemical reaction is given by:

$C_{4} H_{10}$ + $\frac{13}{2} O_{2}$ ---> $4 CO_{2}$ + $5 H_{2}O$

The mass of butane required in the reaction is based on the heat produced by the reaction, which is given to be -1,500 kJ. The minus sign is added because the reaction releases heat (exothermic), which means that the products are in a "lower energy state" than the reactants.

Dividing this with the heat of reaction per mole of butane reacted would give the number of moles butane required. Then, multiplying the answer with the molar mass of butane which is 58 grams/mole, will give the mass of butane required.

Moles of butane = [(-1,500 kJ)/(-2658 kJ/mol butane)]
Moles of butane = 0.5643 moles butane

Mass of butane  = 0.5643 moles butane * 58 grams/mol butane
Mass of butane = 32.73 grams butane

The mass of carbon dioxide ( $CO_{2}$ ) can be determined by multiplying the moles of butane ( $C_{4} H_{10}$ ) with the mole ratio of ( $CO_{2}$ ) produced to the ( $C_{4} H_{10}$ ) reacted, and then with the molar mass of ( $CO_{2}$ ), which is 44 grams/mole.

Mass of carbon dioxide produced
= 0.5643 moles butane * [4 moles $CO_{2}$ / 1 mole $C_{4} H_{10}$ ] * 44 grams/mole $CO_{2}$

Mass of carbon dioxide produced
= 99.32 grams $CO_{2}$

Thus, the mass of butane required is 32.73 grams, and the mass of carbon dioxide produced from the reaction of this amount of butane is 99.32 grams.

4 0

3 years ago

Read 2 more answers

The state of matter in which molecules are attracted to each other but can change position is a

slavikrds [6]

i believe the answer is a liquid

4 0

3 years ago

In an open system the vapor pressure is equal to the

erica [24]

Answer: In an open system the vapor pressure is equal to the outside air pressure.

Explanation:

An open system is a system that is capable of exchanging both matter and energy with its surroundings.

For example, a hot cup of coffee is an open system as the cup is not covered with a lid. Therefore, heat energy from the coffee goes into the surroundings.

Vapor pressure is defined as the ability of a substance to change into vapor state. pressure

Therefore, we can conclude that in an open system the vapor pressure is equal to the outside air pressure.

5 0

3 years ago