*Answer:-*
The sun is about 1/3 the distance from the center of the Milky Way galaxy to its outer edges. It's located in a smaller spiral arm, between two large arms, called the Orion Arm.
Magnesium burns with oxygen to give magnesium oxide based on the following reaction:
2M<span>g</span>+<span>O<span>2 </span></span>........> 2Mg<span>O<span>(s)</span></span>+<span>energy
</span>From the periodic table:
molecular mass of magnesium = 24.3 grams
molecular mass of oxygen = 16 grams
From the reaction:
2 x 24.3 = 48.6 grams of magnesium are required to produce 2(24.3+16) = 80.6 grams of magnesium oxide.
We can know the amount of magnesium oxide produced from 8 grams of magnesium by simply doing cross multiplication as follows:
amount of magnesium oxide = (8 x 80.6) / 48.6 = 13.267 grams
The number of moles of KF needed to prepare the solution is 3 moles
<h3>What is molarity?</h3>
Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the mole of KF </h3>
- Volume = 2500 mL = 2500 / 1000 = 2.5 L
- Molarity = 1.2 M
- Mole of KF =?
Molarity = mole / Volume
1.2 = mole of KF / 2.5
Cross multiply
Mole of KF = 1.2 × 2.5
Mole of KF = 3 moles
Learn more about molarity:
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Answer:
185.49 grams of Zinc would react with 454g (1lb) of copper sulfate
Explanation:
Yo know the following balanced reaction:
CuSO₄(aq)+ Zn(s) →Cu(s) + ZnSO₄(aq)
You can see that by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents and products are part of the reaction:
- CuSO₄: 1 mole
- Zn: 1 mole
- Cu: 1 mole
- ZnSO₄: 1 mole
Being:
- Cu: 63.54 g/mole
- S: 32 g/mole
- O: 16 g/mole
- Zn: 65.37 g/mole
the molar mass of the compounds participating in the reaction is:
- CuSO₄:63.54 g/mole + 32 g/mole + 4*16 g/mole= 159.54 g/mole ≅ 160 g/mole
- Zn: 65.37 g/mole
- Cu: 63.54 g/mole
- ZnSO₄: 65.37 g/mole + 32 g/mole + 4*16 g/mole= 161.37 g/mole
Then, by stoichiometry of the reaction, the following amounts of mass of reagent and product participate in the reaction:
- CuSO₄: 1 moles* 160 g/mole= 160 g
- Zn: 1 mole* 65.37 g/mole= 65.37 g
- Cu: 1 mole* 63.54 g/mole= 63.54 g
- ZnSO₄: 1 mole* 161.37 g/mole= 161.37 g
Now you can apply the following rule of three: if 160 grams of CuSO₄ react with 65.37 grams of Zn by this reaction stoichiometry, 454 grams of CuSO₄ with how much mass of Zn will it react?
mass of Zn= 185.49 grams
<u><em>185.49 grams of Zinc would react with 454g (1lb) of copper sulfate</em></u>
Answer:
4.1 atm = 3,116 mmHg = 415.4 kPa
Explanation:
According to Boyle's law, as volume is increased the pressure of the gas is decreased. That can be expressed as:
P₁ x V₁= P₂ x V₂
Where P₁ and V₁ are the initial pressure and volume respectively, and P₂ and V₂ are final pressure and volume, respectively.
From the problem, we have:
V₁= 50.0 L
V₂= 68.0 L
P₂= 3.0 atm
Thus, we calculate the initial pressure as follows:
P₁= (P₂ x V₂)/V₁= (3.0 atm x 68.0 L)/(50.0 L)= 4.08 atm ≅ 4.1 atm
To transform to mmHg, we know that 1 atm= 760 mmHg:
4.1 atm x 760 mmHg/1 atm = 3,116 mmHg
To transform to kPa we use: 1 atm= 101.325 kPa
4.1 atm x 101.325 kPa = 415.4 kPa
