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Scilla [17]
3 years ago
6

$43,800 at 4.8% for 2 years

Mathematics
2 answers:
Ghella [55]3 years ago
8 0
43800*2=87600
87600*480/100=420480
Mashutka [201]3 years ago
4 0
It would be: P * R * T /100
= 43800 * 4.8 * 2 /100
= 420480 / 100
= 4204.80

So, your final answer is $4204.80

Hope this helps!
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larisa86 [58]
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4 0
3 years ago
How to Solve -5x is greater than or equal to 40
brilliants [131]

Answer:

Step-by-step explanation:

You have to divide -5 from each side so -5/-5x which would be x and divide -5 by 40 which is -8 so x is greater than or equal to -8

4 0
3 years ago
the relationship between temperature in degrees farenheit and degrees celsius is shown in the graph below what is the meaning of
Blababa [14]
Since the graph is not provided and you have not describe which temperature is represented by x or y, we cannot tell what the meaning of any particular coordinate might be. In general, the meaning is the temperature value on the vertical scale that corresponds to zero on the horizontal scale.

For example, if the horizontal (x) scale is °C, then the y-intercept will be 32 °F, the value on that scale that corresponds to 0 °C.

If the horizontal scale is °F, then the y-intercept will be -17 7/9 °C, the value on that scale that corresponds to 0 °F.
3 0
3 years ago
After a bride has interviewed 7 DJs to play at her wedding, her fiance tells her she needs to narrow it down to 4 DJs. In how ma
Alex17521 [72]

Answer:

840

Step-by-step explanation:

Given

DJs = 7

To\ pick = 4

Required

Determine the number of rankings

The term "ranking" as used in this question implies permutation and the required is calculated using:

^nP_r = \frac{n!}{(n-r)!}

Where

n = 7

r = 4

So:

^nP_r = \frac{n!}{(n-r)!}

^7P_4 = \frac{7!}{(7-4)!}

^7P_4 = \frac{7!}{3!}

^7P_4 = \frac{7 * 6 * 5 * 4 * 3!}{3!}

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^7P_4 = 840

<em>Hence, number of ranking is 840</em>

7 0
3 years ago
Enter the explicit rule for the sequence
Softa [21]
Let's take a look at the first few numbers in the sequence based on the given rule:

a_{1}=6\\ a_{2}= \frac{1}{4}(6)\\ a_3= \frac{1}{4}\big( \frac{1}{4}\big)6= \big(\frac{1}{4}\big)^2(6)\\ a_{4}= \frac{1}{4} \big(\frac{1}{4}\big)^26= \big(\frac{1}{4}\big)^3(6)

Inspecting this pattern it seems like the power \frac{1}{4} is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be \big(\frac{1}{4} \big)^{n-1}. We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

a_n=6\big( \frac{1}{4} \big)^{n-1}

Where a_n is the nth number in our sequence.
8 0
4 years ago
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