Let x = mileage
98 >= 35 + .21x
Solving for x:
98 >= 35 + .21x
63 >= .21x
300 >= x
.
This says that if the total mileage is 300 miles or less he will be within his budget.
The first one is (z-7)(z-1)
second: (x+1/3)(x+1/3)
third: (x-1/5)(x-1/5)
fourth: (x-5)(x-2)
X2+5x+y2-y=-2
X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2
(x+5/2)^2+(y-1/2)^2-13/2=-2
(x+5/2)^2+(y-1/2)^2=9/2
So centre =(-5/2,1/2)
Radius=(9/2)^(1/2)
Answer:
see explanation
Step-by-step explanation:
The excluded values are any values of x that make the function undefined
Given

The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the values that x cannot be.
(x + 4)(x - 2)(x - 5) = 0
Equate each factor to zero and solve for x
x + 4 = 0 ⇒ x = - 4
x - 2 = 0 ⇒ x = 2
x - 5 = 0 ⇒ x = 5
x = - 4, x = 2, x = 5 are the excluded values
The main formula for a polynomial ax^my^n+...
the degree is the sum of the highest degree of the polynomial, it is m+n
<span>the degree of x^3y^2+7x^2y^5-3xy^8 is 9, because </span><span>3xy^8 is the term where we can find a highest value of power (8)
so the degree is degree of x, it is 1 + degree of y (it is 8)
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