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Kryger [21]
2 years ago
9

Zoltan has a list of whole numbers, all larger than 0 but smaller than 1000. He notices that every number in his list is either

one-third of another number in the list or three times another number in the list. What is the largest number of different whole numbers that can be on Zoltan's list?
Mathematics
1 answer:
timama [110]2 years ago
4 0

The largest number of different whole numbers that can be on Zoltan's list is 999

<h3>How to determine the largest number?</h3>

The condition is given as:

Number =  1/3 of another number

Or

Number = 3 times another number

This means that the list consists of multiples of 3

The largest multiple of 3 less than 1000 is 999

Hence, the largest number of different whole numbers that can be on Zoltan's list is 999

Read more about whole numbers at:

brainly.com/question/19161857

#SPJ1

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Steven paid 15% down on a car. His down payment was $2,100. How much does he still owe on the car?
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Answer:

315

Step-by-step explanation:

because 15% of 2,100 is 315

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Gala2k [10]

Answer:

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Step-by-step explanation:

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Furkat [3]

Answer:

C: 23 cm

Step-by-step explanation:

This is the answer because:

1) Area of trapezoid is: (base1 + base2)/2 x height

2) In this case, it is 14 + 8 which is 22. 22/2 is 11.

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3 years ago
Read 2 more answers
Please help with geometry. 20 points, and another question worth 98 on my profile!
vovikov84 [41]

Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) PR^{2} =PS*PT

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

so

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The <u>Intersecting Secant-Tangent Theorem,</u> states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

so

In this problem we have that

PR^{2} =PS*PT

Part 3)

we know that

The <u>Tangent-Tangent Theorem</u>  states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

so

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]

4 0
2 years ago
Solve 5kx + 6 = 7kx for x.<br> А. x=3/k<br> в. х = -2/k<br> с. x =-3/k<br> D. x=2/k
slamgirl [31]

Answer:

A.  x = 3/k.

Step-by-step explanation:

5kx + 6 = 7kx

5kx - 5kx + 6 = 7kx - 5kx

6 = 2kx

x = 6 / 2k

x = 3/k.

7 0
2 years ago
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