Answer:
the correct answer is a. more difficult than
Explanation:
Unlike Transaction exposure, economic exposure is difficult to predict and difficult to mitigate in an event of occurence, thus making it harder to manage than transaction exposure.
This is mainly because economic exposure can happen due to various macro economic factors and international political incidents.
D. Economic growth creates the wealth that pays for defense and future investments.
Answer:
The correct answer is the fourth option: It helps in performing corrective or preventive maintenance for a system.
Explanation:
To begin with, a <em>patch management</em> is a technology process used nowadays in the organizations in order to establish a better way to organize the multiple server that it uses currently. It basically focus on the process of regularly performing patch deployment to keep computers up to date therefore that the process detects the missing patches and correct them in order to help the company to reduce system-related failures so that it can improve in productivity and save in the costs associated with it.
A broker works with stocks and the value of a company. The world news effects business status. If oil in Iran was getting pricy then oil companies value with change. If he’s invested in oil companies or is interested, this will affect his choice.
Answer:
a) t = 0.86 sec
b) v = 7.128 m/s
Explanation:
Given data:
Constant acceleration = 5.8 m/s^2
Initial velocity = 2.1 m/s
Displacement = 4.0 m
kinematic equation is given as
![X -X_o = v_o \times t + \frac{1}{2} at^2](https://tex.z-dn.net/?f=X%20-X_o%20%3D%20v_o%20%5Ctimes%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20at%5E2)
![X- X_o = 4.0 m](https://tex.z-dn.net/?f=X-%20X_o%20%3D%20%204.0%20m)
v = 2.1 m/s
a = 5.8 m/s^2
plugging all value in the above relation
![4 = 2.1t + \frac{1}{2} 5.8t^2](https://tex.z-dn.net/?f=4%20%3D%20%202.1t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%205.8t%5E2)
![2.9t^2 + 2.1t - 4 = 0](https://tex.z-dn.net/?f=2.9t%5E2%20%2B%202.1t%20-%204%20%3D%200%20)
solve for t
![t = \frac{-2 \pm \sqrt{2.1^2 -(4\times 2.9 \times (-4)}}{2\times 2.9}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-2%20%5Cpm%20%5Csqrt%7B2.1%5E2%20-%284%5Ctimes%202.9%20%5Ctimes%20%28-4%29%7D%7D%7B2%5Ctimes%202.9%7D)
t = 0.86 sec
b) kinematic equation relating to velocity is given as
![v = v_0 + at](https://tex.z-dn.net/?f=v%20%3D%20v_0%20%2B%20at)
solving for velocity
![v = 2.1 + 5..8\times 0.867](https://tex.z-dn.net/?f=v%20%3D%202.1%20%2B%205..8%5Ctimes%200.867%20)
v = 7.128 m/s