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Vera_Pavlovna [14]
3 years ago
13

Can someone help please AC line ? Maximum 56 points.

Mathematics
1 answer:
jonny [76]3 years ago
7 0

Answer:

18.1 cm

Step-by-step explanation:

Consider a segment parallel to CD and passing through B.

This segment will form a right-angle triangle with A

It's length would be equal to the length of CD (the missing length)

Height of that triangle:

11 - 4 = 7

CD² = 16² - 7²

CD² = 207

CD = sqrt(207)

AC² = AD² + CD²

AC² = 11² + 207

AC² = 328

AC = 2sqrt(82)

Which is roughly 18.1 cm

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Can anyone help me with this problem???
jasenka [17]

Note that x is the hypotenuse of a right triangle. Applying the Pyth. Thm.,


x^2 = 2^2 + 6^2, or x^2 = 4 + 36 = 40.


Thus, the hypotenuse is +sqrt(40), or 2sqrt(10).

8 0
3 years ago
What’s is the value for X+8=12
Luba_88 [7]

Answer:

4

Step-by-step explanation:

X+8= 12

Carry over the 8 and make X the subject.

X= 12-8

X= 4

3 0
3 years ago
Read 2 more answers
Rewrite the rational exponent as a radical by extending the properties of integer exponents. 2 7/8 divided by 2 1/4
VladimirAG [237]
We know the rule of change: a b/c= (ac+b):c
So we have 2 7/8= (2x8+7):8= 23/8
and the second: 2 1/4 = (2x4+1):4= 9/4
We do the division: 23/8: 9/4= 23/8 x 4/9= (23x4):(8x9)= 23/18= 1  5/18
7 0
4 years ago
34
Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

4 0
3 years ago
|x| + 4 > 7 plz help and hurry
Talja [164]

Answer:

The solution is (-\infty,-3)\cup(3,\infty).

Step-by-step explanation:

Given:

The inequality given is:

|x|+4>7

In order to simplify for 'x', we first isolate 'x' on one side.

Adding -4 on both sides, we get:

|x|+4-4>7-4\\\\|x|>3

Now, |x| is an absolute value function which is defined as:

|x|=\left \{ {{-x}\ \ x

Therefore, the given inequality can be rewritten as:

-x > 3\\x and x > 3

Therefore, the solution is (-\infty,-3)\cup(3,\infty).

4 0
3 years ago
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