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lys-0071 [83]
3 years ago
14

A six-sided number cube is tossed and a coin is flipped.

Mathematics
2 answers:
Ann [662]3 years ago
4 0

Answer: The answer is 1/3, on the third attempt on the quiz, that's what it said.

Roman55 [17]3 years ago
4 0

Answer:  The required probability is \dfrac{1}{3}.

Step-by-step explanation:  Given that a six-sided number cube is tossed and a coin is flipped.

We are to find the probability of rolling a number greater than 2 and flipping heads.

The sample space for the event is

S =  {1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T}.

That is, n(S) = 12.

Let, 'A' denotes the event of rolling a number greater than 2 and flipping heads.

So, A = {3H, 4H, 5H, 6H}

That is, n(A) = 4.

Therefore, the probability of rolling a number greater than 2 and flipping heads is given by

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{4}{12}=\dfrac{1}{3}.

The required probability is \dfrac{1}{3}.

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OverLord2011 [107]

50000 tens

5000hundreds

How?

  • 1ten=10

50000 tens:-

\\ \sf\longmapsto 50000(10)=500000

  • 1hundred=100

5000hundreds

\\ \sf\longmapsto 5000(100)=500000

8 0
3 years ago
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3 years ago
The midpoints of an irregular quadrilateral ABCD are connected to form another quadrilateral inside ABCD. Complete the explanati
dem82 [27]

Answer:

Suppose: M, N, P, Q are the midpoints of AB, BC, CD, AD respectively

=> MNPQ is the quadrilateral inside ABCD

connect B to D, ΔABD has : M is the midpoint of AB

                                              Q is the midpoint of AD

=> MQ is the midpoint polygon of ΔABD

=> MQ // BD and MQ = 1/2.BD (1)

ΔBCD has: N is the midpoint of BC

                  P is the midpoint of DC

=> NP is the midpoint polygon of ΔBCD

=> NP // BD and NP = 1/2.BD    (2)

from (1) and (2) => MQ // NP ( //BD)

                            MQ = NP  (=1/2.BD)

=> MNPQ is a parallelogram.​

=>  the quadrilateral inside ABCD is a parallelogram.​

Step-by-step explanation:

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