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3 years ago

10

Need help please! Not sure how to do this

1 answer:

Kisachek [45]3 years ago

3 0

This problem is fairly simple if you know the exponential equation, you start with y=78(.17)^x. the you put 10=78(.17)^x, then you solve for x

10=78(.17)^x
-78
-68=.17^x
divide .17 then you have your answer!!

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A single microvillus is a rod-like structure that is 1.0 μm in height. it has a hemispherical top approximately 0.1 μm in diamet

andre [41]

The surface area of the cylinder that forms the "sides" of the microvillus rod is given by the area of the curved surface of a cylinder with diameter (d) = 0.1 μm and height (h) = <span>1.0 μm.

The curved surface area of a cylinder is given by 2πrh, where r = d / 2 = 0.1 / 2 = 0.05 </span><span>μm.

Thus, the curved surface area is given by

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5 0

3 years ago

I upped the steaks plz answer this, I will give brainiest

Bad White [126]

Answer:

$\displaystyle x = \frac{3}{4}$

Step-by-step explanation:

we are given that

$\displaystyle P = \left(x, - \frac{ \sqrt{7} }{4} \right)$

we want to figure out x

remember that,

In <u>unit</u><u> </u><u>circle</u> x coordinate is considered cos and y coordinate is considered sin

so in order to figure out x we should figure out the value of <u>cos</u> to do we can consider <u>Pythagoras</u><u> trig</u><u> </u><u>indentity</u>

given by

$\displaystyle \sin ^{2} ( \theta) + { \cos}^{2} ( \theta) = 1$

we are given sin=-√7/4 thus

substitute:

$\displaystyle \left( - \frac{ \sqrt{7} }{4} \right) ^{2} + { \cos}^{2} ( \theta) = 1$

simplify square:

$\displaystyle \frac{7}{16} + \cos ^{2} ( \theta) = 1$

move left hand side expression to right hand side and change its sign:

$\displaystyle \cos ^{2} ( \theta) = 1 - \frac{7}{16}$

simplify Substraction:

$\displaystyle \cos ^{2} ( \theta) = \frac{9}{16}$

square root both sides:

$\displaystyle \cos ^{} ( \theta) = \pm\frac{3}{4}$

since in unit circle cos is x and P belongs to Q:IV negative cos isn't applicable

hence,

$\displaystyle x = \frac{3}{4}$

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