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Nataly_w [17]
3 years ago
9

Can 1.33 be 1.3? i need help quick please!?

Mathematics
2 answers:
olganol [36]3 years ago
4 0

Answer:

Step-by-step explanation:

1.33 and 1.3 are not the same, although they share the digits 1.3.

1.33 is accurate to the hundredths place, whereas 1.3 is accurate only to the tenths place.

So:  1.33 and 1.3 are in the same ball park, but are not the same.

neonofarm [45]3 years ago
3 0

Answer:

yes it can be

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Can you help me with this one?
True [87]
Haven’t done this in a while but the first is rational, second is irrational, third is rational, fourth is irrational, fifth is rational, sixth is rational, seventh is irrational
5 0
3 years ago
At the grocery store, Mr. and Mrs. Bailey bought 24 apples and 18 pears. Write a ratio in simplest form to compare apples and pe
Oliga [24]

Answer:

4:3

Step-by-step explanation:

Legit just simplified it.The original ratio is 24:18. First found the greatest common multiple (GCF) and divided both by it. In this case it was 6. So 24/6 = 4 and 18/6 = 3. Now your newly simplified ratio of apples to pears is 4:3.

7 0
3 years ago
Can someone help with this question
NikAS [45]
1st : Find the volume of the rectangular block:
12 × 10 × 20 = 2400 cm^3.

2nd : Find the volume of a cylinder
\pi  {r}^{2} h
Where r is radius & h is height.
so:
\pi \times 2.2 {}^{2}  \times 5.0
= 76.02654222 cm^3

Lastly, divide the volume of the rectangular block by the volume of the cylinder
2400 ÷ 76.026 = 31.5679226

You can't round it up so the answer is F) 31
4 0
3 years ago
Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0
3 years ago
In ΔMNO, m = 50 cm, o = 35 cm and ∠O=83°. Find all possible values of ∠M, to the nearest degree.
Alexxandr [17]

Answer:

No solution

Step-by-step explanation:

I got it right on delta math, just dont write anything and turn that in and it should be correct.

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