The cost of 0.5 kg of bananas is 393.60 Colones as per the given conversion rates
Conversion rate of 1 USD to Costa Rican Colones = 518 Colones
The conversion rate of kg to pounds given in the question: 1 kg = 2.2025 lbs
Cost of one pound of bananas = $0.69
Bananas required to be purchased = 0.5kg
Converting 0.5kg bananas to pounds = 0.5*2.2025 = 1.10125 pounds
Cost of 1.10125 pound of bananas in dollars = 1.10125*0.69 = 0.7598
Cost of 1.1025 pounds of bananas in Colones = 0.7598*518 = 393.60 Colones
Hence, the cost is 393.60
Therefore, the cost of 0.5 kg bananas in Colones is 393.60 Colones
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Answer: Her highest score is on turn two because she used a negative number over a positive and a positive is more than a negative.
Step-by-step explanation:
10>-16
Answer:
Here is the complete question attached with.
The mean score would decrease more than the median score.
Step-by-step explanation:
The numbers for which we have to find the mean and median are:
Here the mean, 
Median,
as median is the middle term if the observations are arranged in ascending order.
Now as the question says that we have to add a zero to see its effect.
So adding a zero we have
Mean 
Median 
,as number of observations is even terms so we will add two middle numbers and divide it with 
.
So we can conclude that the mean is having more variation than the median.
Mean shows as variation of 
where as Median shows a variation of 
only.
So our final answer is option D that is "The mean score would decrease more than the median score."
Answer: exponential decay (choice B)
The variable x in the exponent tells us that this is an exponential function. The fact that the base 1/2 = 0.5 is between 0 and 1 indicates that the value of y will decay or get smaller as x increases. Visually, it graphs out a curve that goes downhill as you read from left to right.
side note: The function f(x) = 7*(1/2)^x can be written as y = 7*(0.5)^x. It has a horizontal asymptote of y = 0 meaning that the curve will get closer and closer to the x axis, but never actually touch it.
