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blondinia [14]
3 years ago
11

Archimedes was asked by his king to figure out a way of telling if people were giving him fake gold objects. That was when Archi

medes discovered his famous principle: an object placed in water displaces the same volume of water as the object’s volume. Explain how Archimedes used this to solve his problem.
Mathematics
1 answer:
klio [65]3 years ago
6 0

Answer:

See explanation below

Step-by-step explanation:

Archimedes was able o obtain the actual volume of the supposedly gold made object by collecting the water displaced by the object as it was sunk on a bowl filled with water to the rim. Then knowing the volume displaced and therefore the volume of the object, he could find the object's density (mass over volume). The mass he could get just by weighting the object. and compare that with the density of any other object made of real gold (like for example a coin) and see if the quotient was the same. The density of both objects should be the same if they are made of the same material.

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Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.
Romashka [77]
By definition, the average change of rate is given by:
 AVR =  \frac{f(x2)-f(x1)}{x2-x1}
 We will calculate AVR for each of the functions.
 We have then:

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f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18
 AVR = \frac{-2-18}{-2-3}
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 f(x) = 3x - 8 interval: [4, 5]:
 f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7
 AVR = \frac{7-4}{5-4}
 AVR = \frac{3}{1}
 AVR = 3

 f(x) = x^2 - 2x interval: [-3, 4]
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f(4) = (4)^2 - 2(4) = 16 - 8 = 8
 AVR = \frac{8-15}{4+3}
 AVR = \frac{-7}{7}
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 f(x) = x^2 - 5 interval: [-1, 1]
 f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4
 AVR = \frac{-4+4}{1+1}
 AVR = \frac{0}{2}
 AVR = 0


 Answer:
 
these functions from the greatest to the least value based on the average rate of change are:
 f(x) = x^2 + 3x
 
f(x) = 3x - 8
 
f(x) = x^2 - 5
 
f(x) = x^2 - 2x
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Step-by-step explanation:

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