The given question can be solve using quadratic formula.
The correct option is (c) 
.
Given:
The given equation is,
---------------------------(1)
Write the general quadratic equation.
Write the quadratic formula.
------------------------------- (2)
Compare equation (1) and (2).
Substitute the value of 
, 
and 
in general quadratic.
Subtract 
from each side of above equation.
Thus, the correct option is (c) .
Learn more about quadratic equation here:
brainly.com/question/17177510
Answer:
50 meters
you have to multiply both numbers in order to find the area
8^2 /2+5(15-7)
=64/2+75-35
=32+40
=72
<span><span>3<span>(<span>5−9</span>)</span></span>+<span>4<span>(<span>4−9</span>)
</span></span></span><span>=<span><span><span>(3)</span><span>(<span>−4</span>)</span></span>+<span>4<span>(<span>4−9</span>)
</span></span></span></span><span>=<span><span>−12</span>+<span>4<span>(<span>4−9</span>)
</span></span></span></span><span>=<span><span>−12</span>+<span><span>(4)</span><span>(<span>−5</span>)
</span></span></span></span><span>=<span><span>−12</span>+<span>−20
</span></span></span><span>=<span>−32
</span></span><span><span>10<span>(<span>9−18</span>)</span></span>−<span>32
</span></span><span>=<span><span><span>(10)</span><span>(<span>−9</span>)</span></span>−<span>32
</span></span></span><span>=<span><span>−90</span>−<span>32
</span></span></span><span>=<span><span>−90</span>−9
</span></span><span>=<span>−<span>99
</span></span></span><span><span>−<span>12<span>(<span>5−7</span>)</span></span></span>−<span>10<span>(<span>2−5</span>)
</span></span></span><span>=<span><span><span>(<span>−12</span>)</span><span>(<span>−2</span>)</span></span>−<span>10<span>(<span>2−5</span>)
</span></span></span></span><span>=<span>24−<span>10<span>(<span>2−5</span>)
</span></span></span></span><span>=<span>24−<span><span>(10)</span><span>(<span>−3</span>)
</span></span></span></span><span>=<span>24−<span>(<span>−30</span>)
</span></span></span><span>=<span>54</span></span>
From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack)
P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace. P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the
probability that they will both be aces? P(AA) = (4/52)(3/51) = 1/221.
1
WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a
king? P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been
removed.
WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick
a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52. The probability of drawing the second queen is also
4/52 and the third is 4/52. We multiply these three individual probabilities together to get P(QQQ) =
P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
What's the probability of being dealt a royal flush in a five card hand from a standard deck of cards? (Note:
A royal flush is a 10, Jack, Queen, King, and Ace of the same suit. A standard deck has 4 suits, each with
13 distinct cards, including these five above.) (NB: The order in which the cards are dealt is unimportant,
and you keep each card as it is dealt -- it's not returned to the deck.)
The probability of drawing any card which could fit into some royal flush is 5/13. Once that card is taken
from the pack, there are 4 possible cards which are useful for making a royal flush with that first card, and
there are 51 cards left in the pack. therefore the probability of drawing a useful second card (given that the
first one was useful) is 4/51. By similar logic you can calculate the probabilities of drawing useful cards for
the other three. The probability of the royal flush is therefore the product of these numbers, or
5/13 * 4/51 * 3/50 * 2/49 * 1/48 = .00000154
Answer: -6
Step-by-step explanation:
2/3 + n + 6 = 3/4
-2/3 -2/3
n + 6 = 1/12
-6 -6
n = - 6
