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AlekseyPX
3 years ago
8

Identify the error by providing a brief description. Then, complete the problem correct

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

True answer: -24

Step-by-step explanation:

<em><u>Showing the error</u></em>

-16-2(-2) – 12   First you need to multiply

8(-2) - 12   The error here is that the wrong numbers are multiplied together

-16-12    Add the negatives together

-28​  Your answer (the incorrect one)

<em><u /></em>

<em><u>The correct way of solving it</u></em>

-16 -2(-2) - 12  Multiply into the parenthesis

-16 + 4 -12   Add the first two numbers

-12 - 12  Add the numbers together

-24  The answer

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first off, let's change all the mixed fractions to "improper" and proceed from there, keep in mind that if we subtract the two bags' weight from the total, what's leftover is the 3rd bag's weight.

\bf \stackrel{mixed}{22\frac{1}{2}}\implies \cfrac{22\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{45}{2}}&#10;\\\\\\&#10;\stackrel{mixed}{6\frac{3}{8}}\implies \cfrac{6\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{51}{8}}&#10;\\\\\\&#10;\stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}\\\\&#10;-------------------------------\\\\

\bf \stackrel{\textit{sum of the two bags}}{\cfrac{51}{8}+\cfrac{13}{4}}\impliedby \textit{our LCD is 8}\implies \cfrac{(1)51+(2)13}{8}&#10;\\\\\\&#10;\cfrac{51+26}{8}\implies \cfrac{77}{8}\\\\&#10;-------------------------------\\\\&#10;\stackrel{total}{\cfrac{45}{2}}~-~\stackrel{two~bags}{\cfrac{77}{8}}\impliedby \textit{our LCD is again 8}\implies \cfrac{(4)45-(1)77}{8}&#10;\\\\\\&#10;\cfrac{180~~-~~77}{8}\implies \cfrac{103}{8}\implies \stackrel{third~bag}{12\frac{7}{8}}
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