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svet-max [94.6K]
3 years ago
14

What is the maximum number of ip addresses that can be assigned to hosts on a local subnet that uses the 255.255.255.224 subnet

mask?
Computers and Technology
1 answer:
FinnZ [79.3K]3 years ago
7 0
30 including the router.
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Frank wants to revise an employee policy. If he wants to inform all of the employees of the change, what type of document will h
nekit [7.7K]

Answer:idk

Explanation:

4 0
3 years ago
Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server
sattari [20]

Answer:

The smallest number of servers required is 3 servers

<em />

Explanation:

Given

Reliability = 99.98\%

Individual Servers = 95\%

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

p = 95\%\\

It should be noted that probabilities always add up to 1;

So,

p + q = 1'

Subtract p from both sides

p - p + q = 1 - p

q = 1 - p

Substitute p = 95\%\\

q = 1 - 95\%

Convert % to fraction

q = 1 - \frac{95}{100}

Convert fraction to decimal

q = 1 - 0.95

q = 0.05

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

p = 99.98\%

Recall that probabilities always add up to 1;

So,

p + q = 1

Subtract q from both sides

p + q - q = 1 - q

p = 1 - q

So,

p = 1 - q = 99.98\%

1 - q = 99.98\%

Let the number of servers be represented with n

The above expression becomes

1 - q^n = 99.98\%

Convert percent to fraction

1 - q^n = \frac{9998}{10000}

Convert fraction to decimal

1 - q^n = 0.9998

Add q^n to both sides

1 - q^n + q^n= 0.9998 + q^n

1 = 0.9998 + q^n

Subtract 0.9998 from both sides

1 - 0.9998 = 0.9998 - 0.9998 + q^n

1 - 0.9998 = q^n

0.0002 = q^n

Recall that q = 0.05

So, the expression becomes

0.0002 = 0.05^n

Take Log of both sides

Log(0.0002) = Log(0.05^n)

From laws of logarithm Loga^b = bLoga

So,

Log(0.0002) = Log(0.05^n) becomes

Log(0.0002) = nLog(0.05)

Divide both sides by Log0.05

\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}

\frac{Log(0.0002)}{Log(0.05)} = n

n = \frac{Log(0.0002)}{Log(0.05)}

n = \frac{-3.69897000434}{-1.30102999566}

n = 2.84310893421

n = 3 (Approximated)

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0
3 years ago
The game begins with the player having 20 POINTS
kompoz [17]

Answer:

Following are the code to this question:

import random#import package for using random method  

def rolling_dice(): #defining method rolling_dice that uses a random number to calculate and add value in dice1 and dice2 variable

   dice1 = random.randint(1,6)

   dice2 = random.randint(1,6)

   return dice1 + dice2

def rolling(): # defining method rolling

   n_roll = 0  # defining num variable that initial value that is 0.

   p = 20 # defining variable p for looping, that points in between 1 and 59

   while p > 0 and p < 60: # defining loop that counts value dice value two times  

       d = rolling_dice()#defining d variable that hold method value

       n_roll+= 1 #defining n_roll that increment n_roll value by 1

       if d == 7 or d == 11:# defining if block that uses the d variable that checks either 7 or 11, player won d in p variable

           p+= d   # use p variable that adds d variable

       elif d == 2 or d == 3 or d == 12:#defining elif block to that checks d variable by using or operator  

           p-= d#defining d variable that decreases d variable variable

       else: # defining else block

           p1 = d # using p1 variable that store d value  

           while True:# defining loop that calculates values

               d = rolling_dice()#defining d variable that holds method values

               n_roll += 1 #increment the n_roll value by 1

               if d == 7:#defining if block that checks d value equal to 7

                   p -= p1#subtract the value of p1 in p variable  

                   break # exit loop

               elif d == p:#defining elif block to check d value is equal to p

                   p += p1#adds the value of p1 in p variable  

                   break#using break keyword

   if p<= 0:#defining if block that checks p-value is less then equal to 0  

       print('Player lost')#using print method

   elif p>= 60:#defining else block that checks p-value is greater than equal to 60

       print('Player won')#using print method to print the value

   print('number of dice rolls:', n_roll)#use print method to print n_rolls value

rolling()

Output:

Player lost

number of dice rolls: 38

Explanation:

In the above-given python code, a method "rolling_dice" is declared, inside the method two-variable "dice1 and dice2" is declared, that uses the random method to calculate the value in both variable and use the return keyword to add both values.

  • In the next step, another method the "rolling"  is declared, inside the method "n_roll and p" is declared that assigns the values and use the two while loop, inside the loop if block is defined that calculates the values.
  • In the next step, a condition block is used that stores value in the p variable and use the print method to print the "n_roll" value.  
8 0
3 years ago
Which studio produced the film The Jazz Singer, the first of many “talkies”?
olga nikolaevna [1]
Warner Brother produced the Jazz Singer. 
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3 years ago
What is one of the main sustainability benefits of using large-scale, cloud computing data centers?
uysha [10]

Cloud computing allows for large chunks of data to be stored in data centers with owners having the ability to access stored information from any devices or location using their login credentials ensuring information are safe, secure and available over a an infinitely long period of time.

  1. Sustainability involves keeping hold of something over a very long period of time.

  • When data or information are saved on online data centers which is made possible by cloud computing. Cloud computing ensures that data isn't saved on an individual's personal memory storage such as local hard drive or memory Cards where it could be lost at anytime.

  • Data is stored online in data centers where it can be accessed over a very long period of time.

Therefore, the ability to get hold of time long information is an essential and important sustainability benefit offered by cloud computing.

Learn more :brainly.com/question/24875533

8 0
3 years ago
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