Question

The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate parameter of 7.6% per hour. How many hours does it take for the size of the sample to double?

Answer 1

Set the growth factor equal to 2
$e^{.076 t} = 2$
Solve for t, Take natural log of both sides
$ln (e^{.076 t}) = ln(2) \\ .076 t = ln(2) \\ ........ \\ t = \frac{ln (2)}{.076}$