A) let the number of cameras sold per day for breakeven be x
Total daily cost = 2000 + 9x
Total daily revenue = 17x
therefore for just covering expenses both cost and revenue must be equal
2000 + 9x = 17x
2000 = 17x - 9x = 8x
x = 2000/8 = 250 cameras
b) increasing production by 50 cameras per day will give a daily profit of;
50 * (17 - 9) = 50 * 8 = $400 (seeing that the fixed daily cost of $2000 remains unchanged)
It's a
Answer:
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Step-by-step explanation:
Hope I helped! :D
Answer: Option B.
Step-by-step explanation:
For this exercise it is important to remember that, by definition, a relation is a function if and only if each input value has an unique output value.
The input values are the values of the variable "x" and the output values are the values of the variable "y".
You can observe in the table shown in the picture, that the input value -2 has two different output values:

Notice that the input vale -1 has two different output values too:

Therefore, based on this, you can conclude that the information given in the table is a relation but not a function.
You know t and I angle t will be 87 and angle w will be 165
2 of the 8 slices of pie A were sold (2/8)
3 of the 6 slices of pie B were sold (3/6)
Both of these fractions can be simplified
2/8 --> 1/4
3/6 --> 1/2
In order to add these two fractions, they must have a common denominator. This can be accomplished by multiplying the second fraction by 2
1/2 --> 2/4
Now we can add the two
1/4 + 2/4 = 3/4
Therefore 3/4 of the pie has been sold. In order to find out how much remains, we must subtract the amount that has been sold from the original amount of pie (2)
2 - 3/4 = 1 1/4 = 1.25