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mrs_skeptik [129]
3 years ago
14

99 POINT QUESTION PLUS BRAINLIEST!!!

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
7 0
The graphs arey=(1/3)x^2
and y=3
they intersect at x=3
so the limits are x=0 and 3
to rotate it about y=k, minus k from every function


area=\pi  \int\limits^3_0 {( \frac{1}{3}x^2-3)^2-(3-3)^2 } \, dx
which evaluates to 72/5pi

A is asnwer
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