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Ilia_Sergeevich [38]

2 years ago

12

The total cost of renting a lawn mower from Lawns Inc. is represented by the function y = 10x + 15, where x represents the numbe

r of hours and y represents the total cost. The cost of renting a lawn mower from Green Lawn is shown in the table.

1 answer:

tangare [24]2 years ago

5 0

Lawns Inc: y=10x+5
Green Lawn: 9x+20

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The enrollment at Ousley Jr. High School dropped by 60 students over a 5-year period. What is the average yearly drop in enrollm

Snezhnost [94]

Answer:

The average yearly drop in enrollment is 12.

Step-by-step explanation:

The average refers to the central value in a group of numbers and with the information provided, you can find the average by dividing the number of students that dropped out of the school by the number of years over which that ocurred:

number of students= 60

number of years= 5

60/5=12

According to this, the answer is that the average yearly drop in enrollment is 12.

3 0

3 years ago

GIVING BRAINLIEST!!!

mezya [45]

Answer:

D, (6,1), (8,8), (12,22), (20,50)

Step-by-step explanation:

Hope this helps!! :D

8 0

2 years ago

If 20% of X is $6, what is 38% of X?

galben [10]

20% of x=6
20/100 of x=6
20x= 600
x=30
38% of 30=11.4

5 0

2 years ago

Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.

tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: $\frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3}$ square units

(22)

Similar to (21)

Area = $216\sqrt{3}$ square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

$altitude=\frac{\sqrt{3}}{2}*side$

$side = \frac{36}{\sqrt{3}}$

Hence, area of the hexagon will be: $648\sqrt{3}$ square units

(24)

Given is the inradius of an equilateral triangle.

$Inradius = \frac{\sqrt{3}}{6}*side$

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = $\frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3}$ square units

4 0

2 years ago

Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

5 0

2 years ago