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Lina20 [59]
3 years ago
8

Evaluate 3x+6y when x= -3, y=6

Mathematics
2 answers:
Tanya [424]3 years ago
6 0

Substitute x for -3, and y for 6. The equation is written as 3(-3)+6(6), then solve.

sesenic [268]3 years ago
3 0

Hey there!!!

Given equation - 3x+6y

x is given as -3

y is given as 6

Plugin these values to get the final answer

3 ( -3 ) + 6 ( 6 )

-9 + 36

= 27

27 is the final and the required answer

Hope my answer helps!

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Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
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Schach [20]

Answer:

25.04

Step-by-step explanation:

26.12-1.08

=25.04

7 0
3 years ago
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Murljashka [212]

Answer:

$755

Step-by-step explanation:

You can use the formula c = 60m + 35 for this. c is the cost and m is the number of months. Since a year is 12 months, 60m = 60*12 = 720. Then add the one time fee of $35. 720 + 35 = 755.

4 0
3 years ago
Classify 4x^5+2x^4-5x^3+12 by number of terms
Semenov [28]
That is 4 terms long. 
7 0
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Jamal states that ax + b = a(x + c), given a, b, and c are not equal to 0. What must be the value of c for Jamal's statement to
Anna35 [415]

ANSWER

For Jamal statement to be true,

c = \frac{b}{a}

EXPLANATION

The given statement is:

ax + b = a(x + c)

We expand the left hand side to obtain,

ax + b = ax + ac

Subtract ax from from both sides of the equation.

b=ac

We know that, a≠0 , so we can divide through by 'a'.

\frac{b}{a}  = c

6 0
3 years ago
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