Answer : The equilibrium concentration of is, 0.16 M
Explanation :
First we have to calculate the concentration of
and,
The given chemical reaction is:
Initial conc. 0.4 2.0 0
At eqm. (0.4-x) (2.0+x) x
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
x = -5.57 and x = 0.24
We are neglecting the value of x = -5.57 because equilibrium concentration can not be more than initial concentration.
Thus, the value of x = 0.24
The equilibrium concentration of = (0.4-x) = (0.4-0.24) = 0.16 M
Therefore, the equilibrium concentration of is, 0.16 M
This answer is true because it's t same amount
One atom of carbon weighs exactly 12/6.022x10^23 = 1.9927x10^-23 grams<span>.</span>
The force acting between two charged particles A and B is 5.2 x 105 newtons. Charges A and B are 2.4 x 102 meters apart. If the charge on particle A is 7.2 x 108 coulombs, what is the charge of particle B? (k 7 9.0 x 109 newton meters?/coulomb)
Answer:
This statement is true.........