Help help help help help<br> What is an action your citizens can take to prevent water waste?

Which one is not a long-term environmental change?

Vilka [71]

swimming is the answer

8 0

2 years ago

Read 2 more answers

I have a mixture of rocks,

Yuki888 [10]

The Rocks have remained on top of the screen, while the sand and water have passed through it.

5 0

2 years ago

Read 2 more answers

1. If we used 0.0100 moles of K2CO3, how many moles of SrCO3 can be expected to form?

faltersainse [42]

Answer:

0.01 moles of SrCO₃

Explanation:

In this excersise we need to propose the reaction:

K₂CO₃ + Sr(NO₃)₂ → 2KNO₃ + SrCO₃

As we only have data about the potassium carbonate we assume the strontium nitrite as the excess reactant.

1 mol of K₂CO₃ react to 1 mol of Sr(NO₃)₂ in order to produce 2 moles of potassium nitrite and 1 mol of strontium carbonate.

Ratio is 1:1. In conclussion,

0.01 mol of K₂CO₃ must produce 0.01 moles of SrCO₃

3 0

2 years ago

KOH + HBr - KBr + H2O<br> Which is the acid in this reaction?

Reptile [31]

Answer:

HBr is a strong acid

Explanation:

KBr is a salt which makes a base . also KOH is a base

7 0

3 years ago

Read 2 more answers

The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.

azamat

Answer:

(a) $m_{gold}=7.322g$

(b)

$V_{gold}=0.379cm^3$

$V_{copper}=0.122cm^3$

(c) $\rho _{coin}=15.94g/cm^3$

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign as shown below:

$m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g$

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

$V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3$

$m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3} \\\\V_{copper}=0.122cm^3$

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

$\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\ \\\rho _{coin}=15.94g/cm^3$

Best regards.

3 0

3 years ago

Read 2 more answers

Help help help help help What is an action your citizens can take to prevent water waste?