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3 years ago

If you can help me with this whole thing i will be forever in your dept

Mathematics

2 answers:

Setler79 [48]3 years ago

5 0

Answer:

Answer:

6 days

210 pages

Step-by-step explanation:

As stipulated by the question, let the number of days Amir has been reading be x and the number of pages he had read to be y.

Now since he reads 35 pages per day.

Then mathematically;

y = 35x

For Jesse, He started reading a day before, this means that the number of days he had read would be x + 1. Since he reads 30 per day, the total number of pages he would have read is 30(x+1)

To find the number of days which is x, we have to assume that at a point in time, the number of books they would have read would be the same meaning that

Also; y = 30(x + 1)

Equating the two situations

35x = 30(x + 1)

35x = 30x + 30

35x -30x = 30

5x = 30

x = 30/5

x = 6 days

This means that it will take Amir 6 days to catch Jese.

The number of books they would have read by then is y = 35x = 30(x + 1)

= 35 * 6 or 30(6+1)

= 210

Step-by-step explanation:

DENIUS [597]3 years ago

5 0

Answer: dude above me copied

Step-by-step explanation:

1. y = 35x

2. y = 30x + 1

3. y = 35x

y = 30 x + 1

4. Its more convenient to substitute y because It's easier.

35x = 30(x + 1)

5. 35x = 30x + 1

35x = 30x + 30

35x -30x = 30

5x = 30

x = 6 (30/5 = 6)

35 x 6 = 210 (y)

6. Both people have read 210 pages and it takes amir 6 days to catch up.

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3 years ago

Is there an error in this statement If x2 = 25, then x = 5.

katen-ka-za [31]

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3 years ago

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Please help with number 39

mr Goodwill [35]

You want to find values of v (number of visors sold) and c (number of caps sold) that satisfy the equation

... 3v + 7c = 4480

In intercept form, this equation is

... v/(1493 1/3) + c/640 = 1 . . . . . divide by 4480

Among other things, this tells us one solution is

... (v, c) = (0, 640)

The least common multiple of 3 and 7 is 21, so decreasing the number of caps sold by some multiple of 3 and increasing the number of visors sold by that same multiple of 7 will result in another possible solution.

The largest multiple of 21 that is less than 4480 is 213. Another possible solution is (0 +213·7, 640 -213·3) = (1491, 1)

We can also pick some number in between, say using 100 as the multiple

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In summary, your three solutions could be

... (visors, caps) = (0, 640), (700, 340), (1491, 1)

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3 years ago

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emmasim [6.3K]

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3 years ago

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3 years ago