(Please help with these) (Im stuck on these)
2 answers:
Answer:
Q1. Option B
Q2. x>3
Q3. 62°
Q4. First three options are correct
Step-by-step explanation:
Q1. Solving the given options one by one. We get,
A. -1/4(y-1/2) = -1/4y + 1/8
B. 1/4(y-2) = 1/4y - 1/2
C. 1/4(y−1/2) = 1/4y - 1/8
D.−1/4(y−2) = -1/4y + 1/2
So, Option B is correct answer.
Q2. Solving the given equation,
5.5x+15.5>32
5.5x + 15.5 -15.5 > 32 -15.5
5.5x > 16.5
x > 3
Q3. Here, The third quadrant is of 90°
So, x = 90° - 28° = 62°
Q4. Since 3% of d = 0.03d
Also, Money given by bank + Money given by his grandmother
= 0.03d + 0.03d = 0.06d
So, total amount of money he get ater one year is d + 0.06d =1.06d
Hence, First three options are correct as 1.06d = d+0.06d = d+0.03d+0.03d
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Answer:
The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance
Null hypothesis is rejected at 0.01 level of significance
There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Mean of the Population = 1900
Given random sample size 'n' = 45
Mean of the sample x⁻ = 1000
Standard deviation of the sample = 225
<u><em>Null Hypothesis</em></u>:-
There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.
<u><em>Alternative Hypothesis</em></u> :-
There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012
<u><em>Step(ii</em></u>):-
Test statistic
t = -900 /33.54 = -26.517
|t| = |-26.517|=26.517
Degrees of freedom
γ = n-1 = 45-1 =44
t₍₀.₀₁ , ₄₄₎ = 2.326
The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance
Null hypothesis is rejected at 0.01 level of significance
There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012