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3 years ago

Joe is 10 years older than James. In 8 years, twice Joe's age will equal three times James's age. How old is each now?

Mathematics

2 answers:

zlopas [31]3 years ago

7 0

Let james be x years old
joe = 10+x
after 8 years
18+x =3(x)
18+x=3x
18=2x
x=9
joe is 19
james is 9

Tresset [83]3 years ago

5 0

Joe's age- 22
James's age- 12

Hope I helped you!

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Which equation has infinitely many solutions?

Verdich [7]

Answer:

The second option (5x+14-4x=23+x-9)

Step-by-step explanation:

For an equation to have infinitely many solutions each side must be exactly the same when simplified.

12+4x=6x+10-2x

Combine alike terms.

12+4x=4x+10

Subtract 4x from each side

12=10

This is not true so this equation has no solutions.

5x+14-4x=23+x-9

Combine alike terms

x+14=14+x

subtract x from each side

14=14

This is true so this equation has infinitely many solutions.

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

5 0

3 years ago

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Which mathematical figure has length but no beginning or end?

Paladinen [302]

Answer:

The correct answer: a line

4 0

2 years ago

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Isaac keeps track of the miles per gallon his car gets per week. He has accumulated the following data:

ipn [44]

we know that

A <u>geometric sequence</u> is a sequence of numbers in which the ratio between consecutive terms is constant

Let

$a1=24 \ a2=24.48\ a3=24.97\ a4=25.47$

$\frac{a2}{a1} = \frac{24.48}{24}= 1.02$

$a2=a1*1.02$

$\frac{a3}{a2} = \frac{24.97}{24.48}= 1.02$

$a3=a2*1.02$

$\frac{a4}{a3} = \frac{25.47}{24.97}= 1.02$

$a4=a3*1.02$

therefore

The common ratio is equal to $1.02$

<u>the answer is</u>

The common ratio is 1.02

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3 years ago

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On a factory floor, 30 out of every 140 toy robots is defective. What percent is defective?

yaroslaw [1]

Answer:

$21.43\%$

Step-by-step explanation:

we know that

To find out the percent of robots which are defective, divided the number of defective robots by the total number of robots and multiply the result by 100

Let

x ----> the number of defective robots

y ----> the total number of robots

p ---> percentage of robots which are defective

$p=\frac{x}{y} (100)$

we have

$x=30\\y=140$

substitute

$p=\frac{30}{140}(100)$

$p=21.43\%$

5 0

4 years ago

Please help, due today

olga_2 [115]

Answer:

[-8,8]

Step-by-step explanation:

domain is the set of x values that the graph covers

This graph starts at -8 and ends at 8 (including those points and all points between them).

That makes the domain [-8,8]

3 0

3 years ago