A scientist set up an experimental ecosystem in a sealed room with no windows. The experimental ecosystem has plants, and animal
1 answer:
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Explanation:
Percentage w/v means that weight of solute present in 100 ml of a solution. Hence, 15% w/v means that 15 gram of solute per 100 ml of solution.
Hence, for 2 L (or 2000 mL) preparation the amount of mass will be calculated as follows.
= 300 g
Thus, we can conclude that weight of Tris-HCL required is 300 g.
Answer:
Probability of having a child with genotype Ww is 50%.
Explanation:
This question involves a single gene coding for hairline shape in humans. The allele for widow's peak hairline (W) is dominant over the allele for straight hairline (w). This means that allele W will mask the phenotypic expression of allele w in a heterozygous state.
In a cross between a mother with genotype, Ww and father with genotype, ww, the following gametes will be produced by each parent:
Mother (Ww)- W and w
Father (ww)- w and w
Using these gametes in a punnet square (see attached image), four possible offsprings will be produced with genotypes: Ww, Ww, ww and ww.
Ww(2) : ww(2) or Ww(1) : ww(1)
Hence, 1 out of 2 children produced by the parents will have a genotype Ww, i.e. 1/2. Therefore, the percentage probability is 1/2 × 100= 50%.
