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Yakvenalex [24]
3 years ago
9

in binomial nomenclature of organisms, every species name includes two words. The first word is the name of the ___.

Biology
2 answers:
murzikaleks [220]3 years ago
8 0
Genus is the correct answer for the blank
adoni [48]3 years ago
7 0

Answer:

genus

Explanation:

Binomial nomenclature is a naming system for all living things. It consists of two parts with the first being the genus and the second being the specific epithet.

Hope that helps.

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Can someone pls check
Schach [20]

Mitosis only

OPTION A

Mitosis is simply the process of cell division.

Meiosis is the process of producing gametes (eggs and sperm), which is important for sexual reproduction.

8 0
2 years ago
Has anyone done this yet ? I need help
Mariana [72]

Answer:

A cube's surface area formula is SA = 6s^2 (s is the length of one of the sides.)

A cube's volume formula is V=a^3

The answer should be 216 for both equations.

Explanation:

Hope this helps. :)

4 0
2 years ago
Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
2 years ago
A gene mutation is a change in the sequence of nucleotides that occurs during cell replication (mitosis and meiosis)within a sin
Shalnov [3]

True

Changes in the transcription of mRNA or the translation of a polypeptide are not considered to be mutations because they are not permanent changes to the cell.

Explanation:

The half-life of mRNA and proteins is short. mRNA has an average of 10 hours of life span while proteins have an average of  several days. Therefore mutation in these biomolecules will only persist as long as this mutated mRNA of protein exists. After its life-span, the molecule is degraded and replaced by a non-mutated mRNA or proteins. This is because the piece of DNA that codes for the mRNA and subsequent protein is not mutated. A mutation on DNA is the permanent kind of mutations because DNA is a highly stable molecule that stores information about the cell.

Learn More:

For more on mutations check out;

brainly.com/question/781815

brainly.com/question/3069156

brainly.com/question/2619737

#LearnWithBrainly

7 0
2 years ago
Peas have two traits that are passed down
natulia [17]

Answer:c

Explanation:

6 0
2 years ago
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