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Serjik [45]
3 years ago
8

What is the slope of the line that passes through the points (-2,5) and (1,4)?

Mathematics
2 answers:
Naddik [55]3 years ago
7 0
-1/3 is the answer of the question
attashe74 [19]3 years ago
6 0

Answer:

-⅓

Step-by-step explanation:

The formula for slope is y²- y¹/x²- x¹. Plug in the numbers for the equation and you have 4-5/1-(-2).

This gives you -1/3.

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Gabrielle wants to buy a new pair of jeans. If the jeans were originally $25.00, but are on sale with a 15% discount, how much w
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3 0
3 years ago
A report by the US Geological Survey indicates that glaciers in Glacier National Park, Montana, are shrinking. Recent estimates
postnew [5]

Answer

a) C

b) B

c) C, E

d) 15.5

e) 0.7

f) 67.7

Step-by-step explanation

a) A linear equation can be written as y=mx+c where m is the slope and c is the intercept on the y-axis. The slope describes how y changes when x changes. A negative value means the it is a decreasing change. In our case, y is A and x is t. Thus, the slope of the equation is m=-0.062. This means that the area of glacier is decreasing by 0.062 \text{km}{}^2 = 62000 \text{m}{}^2 every year since 2000.

b) The A-intercept (= 16.2 \text{km}{}^2) represents the area covered when t=0. But t=0 starting from year 2000. This intercept then represents the area covered by glacier in the year 2000. Therefore, the area covered by glacier in 2000 was 16.2 \text{km}{}^2.

c) A=f(t) means the area covered after year 2000. Setting it to 12 means the area covered after t years is 12 \text{km}{}^2). t is therefore the number of years since 2000 that the total area covered will be 12 \text{km}{}^2).

d) f(12)=16.2−0.062\times12 =16.2-0.744 = =15.456 15.5 \text{km}{}^2 to 1 decimal place.

e) The term involving t represents the disappearing area. In 12 years, the disappeared area is 0.062\times12=0.744 =0.7 \text{km}{}^2 to 1 decimal place.

f) f(t)=16.2−0.062t =12

0.062t = 16.2-12 = 4.2

t = \dfrac{4.2}{0.062}=67.7419\ldots =67.7 years to 1 decimal place.

8 0
3 years ago
Please help mee
NemiM [27]
(2^6)^x=1
(4)^x=1
(4)^0=1
1=1
X=0

(5^0)^x=1
(1)^x=1
x=(-∞,∞)

5 0
2 years ago
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