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Leni [432]
3 years ago
6

What is the solution to this equation x-16=-8

Mathematics
1 answer:
arsen [322]3 years ago
3 0
X-16=-8
Add 16 on both sides 
x=-8+16
And solve; your answer will be
x=8
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Can anyone help me with this math please I will give brainlist
alexandr402 [8]

Answer:

4.5 > 4.420

0.67 < 0.8

0.82 = 0.820

62.4 > 6.24

0.13, 0.3, 0.303, 0.32

0.08, 0.8, 0.82, 8.2

24.54, 24.4, 24.304, 24.24

6.5, 6.25, 6.05, 6.007

Step-by-step explanation:

The most useful way to compare fractions is to add extra zeros at the end.

For example, 0.67 ___ 0.80.

0.80 is obviously bigger than 0.67.

In 24.4, 24.54, 24.304, 24.24, you can add extra zeros as well.

24.400, 24.540, 24.304, 24.240 (This makes it much easier to group the numbers, whether from largest to smallest or smallest to larger).

**REMEMBER TO REMOVE THOSE ZEROS AFTER FINDING YOUR FINAL ANSWER**

7 0
3 years ago
Where do the lines y=2x+1 and y=-5x-6 intersect?
kipiarov [429]
Answer: (-1,-1)

Explanation:

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3 0
3 years ago
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Someone help me with the steps please
Vesna [10]

Answer:

Let u=3x^2-3x

Solution: \frac{1}{6} \sqrt{3x^2-3x}+C

Step-by-step explanation:

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8 0
2 years ago
Find the solutions to the equation below.
yanalaym [24]

Answer:

X=1/2. X=4/3

Step-by-step explanation:

6x2+5X-4=0

6X2+8X-3X-4=0

2x(3x+4) - 1(3x+4)=0

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X=1/2. X=4/3

4 0
3 years ago
Can someone please help me with this problem asap? Thanks!! :))
ivolga24 [154]

Answer: \$4.34

Step-by-step explanation:

We have the following information:

Fredburguer F, milkshake M and an order of fries f costs \$3.72:

F+M+f=\$3.72 (1)

One Fredburguer is equal to a milkshake plus orders of fries:

F=M+2f (2)

Three milshakes is equal to a Fredburguer plus an order of fries:

3M=F+f (3)

And we are asked: If we have a Fredburguer, a milkshake and two orders of fries, how much do we have to pay?

F+M+2f=x (4)

Well with the first three equations we have a system of equations to solve. Let's begin by isolating F from (3):

F=3M-f (5)

Making (2)=(5):

M+2f=3M-f (6)

Isolating f:

f=\frac{2}{3}M (7)

Substituting (7) in (2):

F=M+2(\frac{2}{3}M) (8)

Isolating F:

F=\frac{7}{3}M (9)

Substituting (7) and (9) in (1):

\frac{7}{3}M+M+\frac{2}{3}M=\$3.72 (10)

Isolating M:

M=\$0.93 (11) This is the cost of a Milkshake

Substituting (11) in (7):

f=\frac{2}{3}\$0.93 (12)

f=\$0.62 (13) This is the cost of an order of frieds

Substituting (11) in (9):

F=\frac{7}{3}\$0.93 (14)

F=\$2.17 (15) This is the cost of a Fredburguer

Substituting (11), (13) and  (15) in (4):

\$2.17+\$0.93+2(\$0.62)=x (16)

Finally:

x=\$4.34 This is the cost of a Fredburguer, a milkshake and two orders of fries

8 0
3 years ago
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