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kaheart [24]
3 years ago
9

Daniel needs to sell candy bars For a club fundraiser. She starts with 72 candy bars and begin selling at a constant rate of eig

ht bars each day. Use the segment tool to plot a graph representing the number of candy bars Daniel has left to sell from the time she begins until the candy bars are gone
Mathematics
1 answer:
viktelen [127]3 years ago
3 0
This is an equation that demonstrated the word problem. 8x=72. 8 represents the constant rate of candy bar's she sell each day. X represents the number of days it will take her to sell all the candy hard, and 72 is the number of candy bar's she needs to sell.

It will take Danielle 9 days to sell 72 candy bar's because 9*8=72.

please vote my answer brainliest. thanks!

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Someone please help meeeee
zepelin [54]

Answer:

The number is -1

Step-by-step explanation:

The equation for the first part is (2n+7)2. This is because "twice a number" is 2n and "7 is added" will make it 2n+7. The "sum is multiplied by two" Is multiplying everything by two. This will make it (2n+7)

The second part is  -8n+2. Since a number is multiplied by negative eight it will be -8n. Then it is added by two.

Both equation equal each other the overall equation will be (2n+7)2=-8n+2

You will distribute. making it 4n+14=-8n+2

Add 8n to both sides making it 12n+14=2

subtract 14 from both sides making it 12n=-12

Divide both sides by 12 . making it number=-1

4 0
3 years ago
The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off 2300 employees at its Sam's Club warehouse unit
Advocard [28]

Answer:

(a) The mean is 52 and the median is 55.

(b) The first quartile is 44 and the third quartile is 60.

(c) The value of range is 33 and the inter-quartile range is 16.

(d) The variance is 100.143 and the standard deviation is 10.01.

(e) There are no outliers in the data set.

(f) Yes

Step-by-step explanation:

The data provided is:

S = {55, 56, 44, 43, 44, 56, 60, 62, 57, 45, 36, 38, 50, 69, 65}

(a)

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum x\\=\frac{1}{15}[55+ 56+ 44+ 43+ 44+ 56+ 60+ 62+ 57+ 45 +36 +38 +50 +69+ 65]\\=\frac{780}{15}\\=52

Thus, the mean is 52.

The median for odd set of values is the computed using the formula:

Median=(\frac{n+1}{2})^{th}\ obs.

Arrange the data set in ascending order as follows:

36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60, 62, 65, 69

There are 15 values in the set.

Compute the median value as follows:

Median=(\frac{15+1}{2})^{th}\ obs.=(\frac{16}{2})^{th}\ obs.=8^{th}\ observation

The 8th observation is, 55.

Thus, the median is 55.

(b)

The first quartile is the middle value of the upper-half of the data set.

The upper-half of the data set is:

36, 38, 43, 44, 44, 45, 50

The middle value of the data set is 44.

Thus, the first quartile is 44.

The third quartile is the middle value of the lower-half of the data set.

The upper-half of the data set is:

56, 56, 57, 60, 62, 65, 69

The middle value of the data set is 60.

Thus, the third quartile is 60.

(c)

The range of a data set is the difference between the maximum and minimum value.

Maximum = 69

Minimum = 36

Compute the value of Range as follows:

Range =Maximum-Minimum\\=69-36\\=33

Thus, the value of range is 33.

The inter-quartile range is the difference between the first and third quartile value.

Compute the value of IQR as follows:

IQR=Q_{3}-Q_{1}\\=60-44\\=16

Thus, the inter-quartile range is 16.

(d)

Compute the variance of the data set as follows:

s^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{15-1}[(55-52)^{2}+(56-52)^{2}+...+(65-52)^{2}]\\=100.143

Thus, the variance is 100.143.

Compute the value of standard deviation as follows:

s=\sqrt{s^{2}}=\sqrt{100.143}=10.01

Thus, the standard deviation is 10.01.

(e)

An outlier is a data value that is different from the remaining values.

An outlier is a value that lies below 1.5 IQR of the first quartile or above 1.5 IQR of the third quartile.

Compute the value of Q₁ - 1.5 IQR as follows:

Q_{1}-1.5QR=44-1.5\times 16=20

Compute the value of Q₃ + 1.5 IQR as follows:

Q_{3}+1.5QR=60-1.5\times 16=80

The minimum value is 36 and the maximum is 69.

None of the values is less than 20 or more than 80.

Thus, there are no outliers in the data set.

(f)

Yes, the data provided indicates that the Walmart is meeting its goal for reducing the number of hourly employees

6 0
3 years ago
Simplify the expression write the answer in scientific notation (9×10^7) <br>(7×10^9)
aliina [53]

\text{The scientific notation}\ a\cdot10^k,\ \text{where}\ 1\leq a

6 0
3 years ago
A inversely as x, and y=23 when x=8, find when x=4
Feliz [49]

Answer:

  • y=1/x
  • y=k/x
  • k=yx
  • given y=23,x=8
  • k=23×8=184
  • when x=4
  • y=184/4=46ans

6 0
3 years ago
Quadrilateral DEFG has at least one pair of opposite sides congruent. What types of quadrilaterals meet this condition?​
zhuklara [117]

Answer:

Parallelogram, Rectangle, Square, Rhombus, Trapezoid. ... ANSWER Trapezoid: there is one pair of parallel sides

Step-by-step explanation:

there is one pair of parallel sides

6 0
2 years ago
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