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kykrilka [37]
3 years ago
14

Does 3 tenths equal 4 fifths?

Mathematics
2 answers:
velikii [3]3 years ago
7 0
No. 3/10 doesn't equal 4/5. 3/10 is just 3/10 and cannot change.
Hope I helped!
-Drey
OleMash [197]3 years ago
6 0
No it does not equal 4 fifths
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3 years ago
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Find an expression which represents the difference when (-5x-y) is subtracted from (9x+2y) in simplest terms.
AnnyKZ [126]

Answer:

4x+y add like terms ... -5+9=4 and  -y(or -1)+2y=y

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2 years ago
The area of the larger circle is??
nevsk [136]

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radius of large circle is doubled so it will be 32 m


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answer

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3 years ago
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Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
2 years ago
F(x)=2x an$ g(x)=2x+3,what is the value of f(g(-8))
Fudgin [204]

First plug in g(x) into f(x)

F((g(x))=2(2x+3)

And now you plug in -8

F(g(-8))=2(-16+3)

F(g(-8))=2(-13)

F(g(-8))=-26

6 0
2 years ago
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