5 and 2/10 converted into decimal notation would be, 5.2
The first answer is 3/34 sec and the second answer is 15/34 sec.
Set up a proportion for these problems. For the first question,
340/1 = 30/x
Cross multiply:
340*x = 1*30
340x = 30
Divide both sides by 340:
340x/340=30/340
x = 30/340 = 3/34
For the second question,
340/1 = 150/x
Cross multiply:
340*x = 150*1
340x=150
Divide both sides by 340:
340x/340 = 150/340
x = 150/340 = 15/34
Answer:
(a) The mean and standard deviation of the pallet weight are 3000 lb and 10.95 lb respectively.
(b) The probability that the pallet weight (W) will exceed 3015 lb is 0.085.
Step-by-step explanation:
Let the random variable <em>X</em> denote the weight of the parts.
The random variable <em>X</em> is normally distributed with parameters, <em>μ</em> = 1 lb and <em>σ</em> = 0.20 lb.
It is provided that a shipping pallet holds 10 boxes and each box holds 300 parts of different types.
That is, there are a total of 300 × 10 = 3000 parts in a pallet.
(a)
Compute the mean and standard deviation of the pallet weight as follows:
Mean of the pallet weight = n × E (X)

Standard deviation of the pallet weight = 

Thus, the mean and standard deviation of the pallet weight are 3000 lb and 10.95 lb respectively.
(b)
Compute the probability that the pallet weight (W) will exceed 3015 lb as follows:


*Use a <em>z</em>-table.
Thus, the probability that the pallet weight (W) will exceed 3015 lb is 0.085.
Answer:
The correct answer is 3 (just the number 3)
Step-by-step explanation:
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Answer:
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Step-by-step explanation: