Using the gas laws, the volume of nitrogen produced is 6.6 L.
<h3>What is the product of a reaction?</h3>
We know that the product of a reaction is obtained from the balanced reaction equation. The reactants combine together to yield the products hence we have; N2 + 3H2 ----> 2NH3
We know that 1 mole of hydrogen occupies 22.4 L
x moles of hydrogen occupies 25500 L
x = 1 mole * 25500 L/ 22.4 L
x = 1138.4 moles
If 3 mole of hydrogen reacts with 1 mole of nitrogen
1138.4 moles reacts with 1138.4 moles * 1 mole/ 3 moles = 379.5 moles
Mass of nitrogen = 379.5 moles * 28 g/mol = 10626 g
Now 3 moles of hydrogen produces 44.8 L of NH3
1138.4 moles produces 1138.4 moles * 44.8 L/ 3 moles = 17000 L
Now;
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V2 = P1V1T2/P2T1
V2 = 1 * 17000 * 848/5.5 * 273
V2 =9601 L
2) 2NH4NNO3(s) ---> 4H2O(g) + 2N2(g) + O2(g)
Number of moles = 12g/ 80 g/mol = 0.15 moles
Now;
2 moles of NH4NNO3 produced 2 moles of nitrogen hence 0.15 moles of N2 was produced.
1 mole of N2 occupies 22.4 L
0.15 moles of N2 occupies 0.15 moles * 22.4 L/1 mole = 3.36 L
P1 = 760 torr
V1 = 3.36 L
T1 = 273 K
P2 = 745 torr
T2 = 527 degrees or 800 K
V2 = ?
V2 = P1V1T2/P2T1
V2 = 760 * 3.36 * 527/745 * 273
V2 = 6.6 L
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