1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AfilCa [17]
3 years ago
7

Marcia is given an incomplete chemical equation that includes the number of nitrogen atoms present in the products of the reacti

on. How can she conclude that the reaction started with three nitrogen atoms?
Chemistry
2 answers:
Elden [556K]3 years ago
8 0
If the products contain 3 nitrogen atoms, then so did the reactants since overall mass is conserved in a chemical reaction.
mylen [45]3 years ago
6 0

Sample response:

There would have to be three nitrogen atoms in the products. The law of conservation of matter states that the amount of substance before a reaction occurs should be the same as the amount of substance after the reaction.

hope this helps! Have a great one :D

You might be interested in
Iodine-131 is a radioactive isotope that is used in the treatment of cancer of the thyroid. The natural tendency of the thyroid
Finger [1]

Answer:

a) Binding Energy = 1084.266 MeV

b) Binding energy per nucleon = 8.28 MeV

Explanation:

Binding Energy, BE = \triangle M * 931.5

Where ΔM = Mass defect of Iodine-131

The mass of iodine-131 = 130.906124 u.

Number of protons in Iodine-131 = 53

Number of neutrons in Iodine-131 = 78

Mass of a proton = 1.007276 u

Mass of neutron = 1.008664 u

Total mass of the 53 protons in Iodine-131 = (53*1.007276)

Total mass of the 53 protons in Iodine-131 =  53.39 u

Total mass of the 78 protons in Iodine-131 = (78*1.008664)

Total mass of the 78 protons in Iodine-131 = 78.68 u

\triangle M = (53.39 + 78.68) - 130.906124\\\triangle M = 1.164 u

Binding Energy = 1.164 * 931.5

Binding Energy = 1084.266 MeV

b) Binding Energy per nucleon

The mass of the nucleon of iodine 131 = 130.906124

Binding Energy per nucleon =  1084.266/130.906124

Binding energy per nucleon = 8.28 MeV

5 0
4 years ago
POINTS!!!
lisabon 2012 [21]
The answer is selenium which is D
8 0
3 years ago
How many moles of copper are present in 75.0g Cu? Show your complete calculation and give the answer in the correct number of si
velikii [3]

Answer:

The answer to your question is 1.2 moles of copper

Explanation:

Data

mass of copper = 75 g

moles = ?

Process

1.- Look in the periodic table for the atomic mass of copper.

Atomic mass = 63.55 g/mol

2.- Use proportions to determine the moles of copper in 75 g

                          63.55 g of copper -------------------- 1 mol

                          75 g of copper       --------------------  x

Use cross multiplication

                          x = (75 x 1) / 63.55

                          x = 75 / 63.55

                          x = 1.18 moles ≈ 1.2 moles of copper

3 0
4 years ago
Read 2 more answers
A chemist pours 1 mol of zinc granules into one beaker and 1 mol of zinc chloride powder into another beaker. What do the two sa
Oksana_A [137]
Answer is: <span> two samples have in common same amount of substance and same number of particles.
1) There are same amount of substance in both beakers:
n(Zn) = 1 mol.
n(ZnCl</span>₂) = 1 mol.
2) There are same number of particles (atoms, molecules, ions) in both beakers:
N(Zn) = n(Zn) · Na.
N(Zn) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ atoms of zinc.
N(ZnCl₂) = n(ZnCl₂) · Na.
N(ZnCl₂) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ molecules of zinc(II) chloride.
Na - Avogadro number.


5 0
4 years ago
Read 2 more answers
6. A balloon filled with air has a volume of 3.25 L at 30°C. It is placed in a freezer at
Viefleur [7K]

Answer:

2.82 L

T₁ = 303 K

T₂ = 263 K

The final volume is smaller.

Explanation:

Step 1: Given data

  • Initial temperature (T₁): 30 °C
  • Initial volume (V₁): 3.25 L
  • Final temperature (T₂): -10 °C
  • Final volume (V₂): ?

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

T₁: K = 30°C + 273.15 = 303 K

T₂: K = -10°C + 273.15 = 263 K

Step 3: Calculate the final volume of the balloon

Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 3.25 L × 263 K/303 K = 2.82 L

7 0
3 years ago
Other questions:
  • Which of the following goes on the y-axis of a graph?
    12·2 answers
  • Why we need coal to generate electricity?
    6·2 answers
  • An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is t
    5·1 answer
  • The color of the light changes in the scenario because a volcano erupts. The light is the_____variable.
    11·2 answers
  • A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She
    5·1 answer
  • 7. the answer is not D
    10·1 answer
  • 36. Which statement is incorrect in nuclear decay situations of a nucleus? a. Nucleus has too many protrons = a positron emissio
    6·1 answer
  • Which of the following BEST supports the Big bang theory of the origin of the universe?
    6·1 answer
  • The carbon dioxide molecules that bind to the hemoglobin molecule are attached to the __________ units.
    11·1 answer
  • In an oxidation-reduction reaction, the oxidized reagent _____, and the reduced reagent _____
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!